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Research Article

New Results About Imaginary Value of the Second Axiomatic Zero of the Zeta Function and the Fifth Bernoulli Number

[version 1; peer review: awaiting peer review]
PUBLISHED 10 Jan 2026
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This article is included in the Fallujah Multidisciplinary Science and Innovation gateway.

Abstract

This paper introduces two theorems in number theory about zeta at − 4 and the fifth Bernoulli number B 5 , showing that the zeta function ζ ( − 4 ) has two complex values and that the fifth Bernoulli number is not zero but alsohas two complex values.

The current research concludes that the zeta function ζ ( − 4 ) has two imaginary values that are different from what was previously known to mathematicians, which was believed to be equal to zero, whereas, ζ ( − 4 ) = - i 558 , ζ ( − 4 ) = - i 2232

Therefore, the fifth Bernoulli number is not equal to zero and has two values: B 5 = − 5 i 558 and B 5 = − 5 i 2232 .

Keywords

Zeta function, Bernoulli numbers, trivial zeros.

1. Introduction

In 1713 Swedish mathematician Jacob Bernoulli and Japanese mathematician Seki Takakazu independently discovered numbers now called Bernoulli numbers through their work on the power series of integers 1m+2m+3m++nm . After their work, they accidentally discovered the values of these numbers and, through law1:

Sm(n1)=1m+1k=1m(m+1k)Bknmk+1
determined the final values of these numbers, and concluded that all odd Bernoulli numbers are zero except for the first Bernoulli number B1=12 , and even Bernoulli numbers have the following values2:
B0=1,B1=12,B2=16,B3=0,B4=130,B5=0,B6=142

In 1734, Swiss mathematician Leonardo Euler formulated the zeta function:

ζ(s)=n=11ns,
where, s .

Euler defined a zeta function in the domain of real numbers. He succeeded in cleverly linking the zeta function to prime numbers through the law that he derived.

ζ(s)=p1(1ps)

He also succeeded in solving the Basel problem, which was posed in Basel City, and provided proof of the result using the zeta function, where3

ζ(2)=1+122+132+142+=π26

By studying the zeta function and linking it with Bernoulli numbers, Euler succeeded in deducing two of the most important laws. Through this study, he succeeded in linking the Bernoulli numbers with the zeta function.

(1)
ζ(2k)=(1)k+1(2π)2kB2k2(2k)!;k=1,2,3,
(2)
ζ(k)=(1)kBk+1k+1;k=0,1,2,3,

From this, he concluded that the zeta function at 1 equals 112 .4

ζ(1)=1+2+3+4+=112

if k=1 then, ζ(1)=(1)1B22=1/62=112

In 1859, German scientist Bernard Riemann extended the range of functions to include imaginary numbers as follows:

ζ(s)=n=11ns,
where, s .

Riemann extended the range of the function’s inputs to include imaginary numbers and stated that all non-trivial zeros lie on the critical line, which was named after him for the results he provided on this function. The Riemann conjecture is considered to be an unsolved mathematical problem.5

Ramanujan presented a proof in which he proved that the zeta function at the negative number 1 is equal to 112 , where

ζ(1)=1+2+3+4+=112

Using special sums in a specific manner, as in,6 It should also be emphasized that Euler presented a proof in which he showed that the zeta function at 1 equals 112 , based on Bernoulli numbers, and Ramanujan proved that the zeta function at 1 equals 112 using sums.

Another researcher presented a refutation of what are called axiomatic zeros, whose values depend on Bernoulli numbers7 using partial sums. The researcher presented a proof to calculate the value of the zeta function at the number 2 and proved that its value is not equal to zero as Euler extracted it using his second law based on Bernoulli numbers, but rather equals an imaginary value of i84 . The researcher also proved that the third Bernoulli number is not zero based on Euler’s second law, considering that zeta is known and the Bernoulli number is unknown, thus concluding that the third Bernoulli number is equal to i28 .

2. The main results

In this section, two theorems are proved and show that the zeta function at (4) has two complex values and that the fifth Bernoulli number B5 is not zero but has two complex values 5i558and5i2232 .

Theorem 1:

Zeta function at 4 has two values -i558and-i2232

Proof:

ζ(s)=n=11ns , where s according to the Euler definition.

ζ(4)=n=11n4=n=1n4=1+16+81+256+625+1296+

From,8

(3)
η(s)=n=1(1)n+1ns;s=4η(4)=n=1(1)n+1n4=116+81256+6251296+ζ(4)η(4)=32+512+2592+=32(1+16+81+)ζ(4)32ζ(4)=η(4)ζ(4)=η(4)31

Now,

η(4)=116+81256+6251296+
1=[1(1)1(1)]
116=15={[(1+2)(4)+(1+2)(1)][(1)1+1(1)]}
116+81=66={[(1+2+3)(9)+(1+2+3)(1+1)][(1)1+1+1(1)]}
116+81256=190={[(1+2+3+4)(16)+(1+2+3+4)(1+1+1)][(1)1+1+1+1(1)]}
116+81256+625=435={[(1+2+3+4+5)(25)+(1+2+3+4+5)(1+1+1+1)][(1)1+1+1+1+1(1)]}
and so on,
(4)
η(4)={(1+2+3+)[(1+2+3+)+(1+2+)]+[(1+2+3+)(1+1+)]}[(1)1+1+1+(1)]
η(4)={ζ(1)[ζ(1)+ζ(1)]+ζ(1)ζ(0)}[(1)ζ(0)(1)]
η(4)={112[112+112]+11212}[(1)12(1)]
η(4)=i18

Put in Equation (3) we get

(5)
ζ(4)=i/1831=i558

By Equation (4):

1=[1(1)1(1)]116=15={[(1+2)(1+2+1+22)+(1+2)(1)][(1)1+1(1)]}116+81=66={[(1+2+3)(1+2+3+1+2+33)+(1+2+3)(1+1)][(1)1+1+1(1)]}116+81256=190={[(1+2+3+4)(1+2+3+4+1+2+3+44)+(1+2+3+4)(1+1+1)][(1)1+1+1+1(1)]}116+81256+625=435={[(1+2+3+4+5)(1+2+3+4+5+1+2+3+4+55)+(1+2+3+4+5)(1+1+1+1)][(1)1+1+1+1+1(1)]}
and so on,
(6)
η(4)={(1+2+3+)[(1+2+3+)+[1+2+3+)(1+1+1+)]]+[(1+2+3+)(1+1+)]}[(1)1+1+1+(1)]
η(4)={(ζ(1))[(ζ(1))+[ζ(1))(ζ(0))]]+[(ζ(1))(ζ(0))]}[(1)ζ(0)(1)]η(4)={(112)[(112)+[112(12)]]+[(112)(12)]}[(1)12(1)]η(4)=i72

Put in Equation (3) we get

(7)
ζ(4)=i/7231=i2232

Theorem 2:

The fifth Bernoulli number, B5 is not zero but has two values: 5i558and5i2232.

Proof:

Using (2) ζ(k)=(1)kBk+1k+1 being ζ(4)=(1)4B55

Since ζ(4)=i558 from (5) , we get, B5=5i558.

And, Since ζ(4)=i2232 from (7) , we get, B5=5i2232

3. Conclusions

We conclude from the current research that the zeta function ζ(4) has two imaginary values that are different from what was previously known to mathematicians, which was believed to be equal to zero, whereas,

ζ(4)=-i558,ζ(4)=-i2232

Therefore, the fifth Bernoulli number is not equal to zero and has two values: B5=5i558 and B5=5i2232 .

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Tuma AA and Salman SM. New Results About Imaginary Value of the Second Axiomatic Zero of the Zeta Function and the Fifth Bernoulli Number [version 1; peer review: awaiting peer review]. F1000Research 2026, 15:46 (https://doi.org/10.12688/f1000research.172983.1)
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Comments on this article Comments (0)

Version 1
VERSION 1 PUBLISHED 10 Jan 2026
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Alongside their report, reviewers assign a status to the article:
Approved - the paper is scientifically sound in its current form and only minor, if any, improvements are suggested
Approved with reservations - A number of small changes, sometimes more significant revisions are required to address specific details and improve the papers academic merit.
Not approved - fundamental flaws in the paper seriously undermine the findings and conclusions
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