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Research Article

Local Multiset Dimension of Amalgamation Graphs

[version 1; peer review: 1 approved, 1 approved with reservations]
PUBLISHED 24 Jan 2023
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Abstract

\textbf{Background}: One of the topics of distance in graphs is the resolving set problem. Suppose the set $W=\{s_1,s_2,…,s_k\}\subset V(G)$, the vertex representations of $\in V(G)$ is $r_m(x|W)=\{d(x,s_1),d(x,s_2),…,d(x,s_k)\}$, where $d(x,s_i)$ is the length of the shortest path of the vertex $x$ and the vertex in $W$ together with their multiplicity. The set $W$ is called a local $m$-resolving set of graphs $G$ if $r_m (v|W)\neq r_m (u|W)$ for $uv\in E(G)$. The local $m$-resolving set having minimum cardinality is called the local multiset basis and its cardinality is called the local multiset dimension of $G$, denoted by $md_l(G)$. Thus, if $G$ has an infinite local multiset dimension and then we write $md_l (G)=\infty$. \\ \textbf{Methods}: This research is pure research with exploration design. There are several stages in this research, namely we choose the special graph which is operated by amalgamation and the set of vertices and edges of amalgamation of graphs; determine the set $W\subset V(G)$; determine the vertex representation of two adjacent vertices in $G$; and prove the theorem.\\ \textbf{Results}: The results of this research are an upper bound of local multiset dimension of the amalgamation of graphs namely $md_l(Amal(G,v,m))\leq m.md_l(G)$ and their exact value of local multiset dimension of some families of graphs namely $md_l(Amal(P_n,v,m))=1$, $md_l(Amal(K_n,v,m))=\infty$, $md_l(Amal(W_n,v,m))=m. md_l(W_n)$, $md_l(Amal(F_n,v,m))=m. md_l(F_n)$ for $d(v)=n$, $md_l(Amal(F_n,v,m))=m. \lfloor\frac{n}{4}\rfloor$. \\ \textbf{Conclusions}: We have found the upper bound of a local multiset dimension. There are some graphs which attain the upper bound of local multiset dimension namely wheel graphs\\

Keywords

local m-resolving set; local multiset dimension; amalgamation graph.

Introduction

In this paper, we study the local multiset dimension of the amalgamation of graphs. One of the topics of distance in graphs is resolving set problems. This topic has many application in science and technology namely in the navigation of robots, chemistry structure, and computer sciences. The application of metric dimension in networks is the navigation of robots. Suppose, we represent a place as a vertex and a connection between place is represented by an edge. The minimum numbers of robots required to locate each vertex in the networks is part of the resolving set problems. More details of this application can be seen.1

Several applications of resolving sets in chemistry are the substructures of a chemical compound which can be denoted by a set of functional groups. Moreover, in a chemical structure or molecular graph edges and vertices are known as bonds and atoms, respectively. Furthermore, the sub graphs are simply deliberated as substructures and functional groups. Now after altering the position of functional groups, the formed collections of compounds are distinguished as substructures being similar to each other. Later on using the method of traditional view, we can investigate if any two compounds hold the same functional group at the same point, while in drugs discovery comparative statements contributes a critical part to determine pharmacological activities related to the feature of compounds.2

All graphs G are simple, finite, and connected. Given that the vertex set V (G) and the edge set E(G), we write G = (V, E). The distance of u and v, denoted by d(u, v) is the length of the shortest path of the vertices u to v. For the set W = {s1, s2, …, sk} ⊂ V (G), the vertex representations of the vertex x to the set W is an ordered k-tuple, r(x|W) = (d(x, s1), d(x, s2), …, d(x, sk)). The set W is called the resolving set of G if all vertices of G have different vertex representations. The resolving set having minimum cardinality is called basis and its cardinality is called metric dimension of G, denoted by dim(G).3 Okamoto et al.4 introduced the new variant of resolving set problems which is called local resolving set problems. In his paper, this notion is called a local multiset dimension of graphs G. The set W is called a local resolving set if for every xyE(G), r(x|W)≠r(y|W). The local resolving set having minimum cardinality is called local basis and it’s cardinality is called local metric dimension of G and denoted by ldim(G).

Simanjuntak et al.5 defined multiset dimension of graphs G. Suppose the set W=s1s2skVG, the vertex representations of a vertex xV (G) to the set W is the multiset rmxW=dxs1dxs2dxsk where d(x, si) is the length of the shortest path of the vertex x and the vertex in W together with their multiplicities. The set W is called a m-resolving set if for every xyE(G), rm(x|W)≠rm(y|W). If G has a m-resolving set then an m-resolving set having minimum cardinality is called a multiset basis and it’s cardinality is called the multiset dimension of graphs G and denoted by md(G); otherwise we say that G has an infinite multiset dimension and we write mdG=. Alfarisi et al.6 studied the multiset dimension of almost hypercube graphs. Later, Alfarisi et al.7 extended a new notion based on the multiset dimension of G, namely a local multiset dimension. Suppose the set W=s1s2skVG, the vertex representations of a vertex xV (G) to the set W is rm(x|W) = {d(x, s1), d(x, s2), …, d(x, sk)}. The set W is called a local m-resolving set of G if rm(v|W)≠rm(u|W) for uvE(G). The local m-resolving set having minimum cardinality is called the local multiset basis and it’s cardinality is called the local multiset dimension, denoted by mdl(G): otherwise we say that G has an infinite local multiset dimension and we write mdlG=.

We illustrate this concept in Figure 1. In this case, the m-resolving set is W = {v2, v3, v6}, shown in Figure 1(a). The multiset dimension is md(G) = 3. The representations of vV (G) with respect to W are all distinct. For the local multiset dimension, we only need to make sure the adjacent vertices have distinct representations. Thus, we could have the local m-resolving set W = {v1}, shown in Figure 1(b). Thus, the local multiset dimension is μl(G) = 1.

rv1Π=0,rv2Π=1,rv3Π=2
rv4Π=1,rv5Π=2,rv6Π=1
c56c433b-7ca3-45fb-91b9-cf11af9f25e0_figure1.gif

Figure 1. (a) A graph with multiset dimension 3; (b) A graph with local multiset dimension 1.

We have some results on the local multiset dimension of some known graphs namely path, star, tree, and cycle and also the local multiset dimension of graph operations namely, cartesian product,7 m-shadow graph.8 Adawiyah et al.9 also studied local multiset dimension of unicyclic graphs. The followings are some results which is used for proving the new results in this study.

Lemma 0.1

Let G be a connected graphs and WV (G). If W contains a resolving set of G, then W is a resolving set of G.10

Proposition 0.1

A graph is bipartite if and only if it contains no odd cycle.11

Theorem 0.1

The local multiset dimension of G is one if and only if G is a bipartite graph.12

Theorem 0.2

If T is tree graph with order n, then mdl(T) = 1.12

Proposition 0.2

Let Kn be a complete graph with n ≥ 3, we have mdlKn=.6

Definition 0.1

Let (Gi) be a finite collection of graphs and each Gi has a fixed vertex v called a terminal. The amalgamation Amal (Gi, v, m) is formed by taking of all the Gi and identifying their terminal.

Figure 2 is an example of an amalgamation graph with isomorphic and non-isomorphic graph.

c56c433b-7ca3-45fb-91b9-cf11af9f25e0_figure2.gif

Figure 2. a) Amal (Hj, v0, j) with j = 1, 2, 3 and b) Amal(H1, v0, 1, 4).

Methods

The nature of the methods follows an extrapolative design. There are several stages in this research as follows:

  • 1. Choose the special graph which is operated by amalgamation;

  • 2. Determining the set of vertices and edges of amalgamation of graphs;

  • 3. Determining the set WV (G);

  • 4. Determining the vertex representation of two adjacent vertices in G;

  • 5. Proving the theorem.

The flowchart of this method can be seen in Figure 3.

c56c433b-7ca3-45fb-91b9-cf11af9f25e0_figure3.gif

Figure 3. Flowchart of the extrapolate design of the study.

Results

In this section, we investigated the local multiset dimension of graph amalgamation. We provide an upper bound of local multiset dimension of Amal(G, v, m) and we show that the upper bound is sharp. We also determined the exact value of the local multiset dimension of Amal(G, v, m) for some certain graphs namely path, complete graph, fan graph, and wheel graph. The following theorem provides a sharp upper bound of Amal(G, v, m).

Lemma 0.2

Let m and n be two integers with m ≥ 2 and n ≥ 3. Let G be a connected graph of order n and v be a terminal vertex of G, then mdl (Amal(G, v, m)) ≤ m.mdl(G)

Proof.

Let

VAmalGvm=uuj,i1jm1in1
and
EAmalGvm=j=1j=mEG
where v denote the identified vertex or terminal vertex.

We show that mdl (Amal(G, v, m)) ≤ m.mdl(G). Let W be the local m-resolving set of G. Amal(G, v, m) has m copies of G, such that S=j=1j=mWj. We take identified vertex vW, thus two adjacent vertices uk,r, uk,sV (G) have different representation. There are two conditions for uk,r, uk,sV (G) to terminal vertex.

  • 1. For uk,r, uk,sV (G) and d (uk,r, v) = d (uk,s, v), then d (uk,r, w) = d (uk,s, w) for wSWk. Thus, rm (uk,r|S)≠rm (uk,s|S).

  • 2. For uk,r, uk,sV (G) and d (uk,r, v)≠d (uk,s, v), then d (uk,r, w)≠d (uk,s, w) for wSWk. Thus, rm (uk,r|S)≠rm (uk,s|S).

Based on 1 and 2 that S=j=1j=mWj is the local m-resolving set of Amal(G, v, m). Thus, mdl (Amal(G, v, m)) ≤ m.mdl(G). □

Theorem 0.3

If Amal (Pn, v, m) is an amalgamation of m paths, then mdl (Amal(Pn, v, m)) = 1

Proof.

Let

VAmalPnvm=uuj,i1jm1in1
and
EAmalPnvm=j=1j=mEPnj}

Since Pn is bipartite graph, then Amal (Pn, v, m) is bipartite graph. Based on Theorem 0.1 that mdl (Amal(Pn, v, m)) = 1. □

Theorem 0.4

If Amal (Kn, v, m) is an amalgamation of m complete graphs, then mdlAmalKnvm=

Proof.

Let

VAmalKnvm=uuj,i1jm1in1
and
EAmalKnvm=j=1j=mEKnj}

For two adjacent vertices x, yV ((Kn)k) with k ∈ [1, m] such that we have d(x, u) = d(y, u). Since d(x, u) = d(y, u), then d(x, w) = d(y, w) with wV (Amal (Kn, v, m)). Thus, rm(x|W)≠rm(y|W). □

Consider graph Amal (Wn, v, m) where v is a center vertex of Wn. Let V (Amal (Wn, v, m)) = {v} ∪ {uj, i;1 ≤ jm and 1 ≤ in} such that EAmalWnvm=j=1j=mE(Wnj).

Theorem 0.5

Let m and n be two integers with m ≥ 2 and n ≥ 3. Let Wn be a wheel graph of order n + 1 and vV (Wn) where v is a center vertex of Wn, then mdl (Amal (Wn, v, m)) = m.mdl (Wn).

Proof.

Let W be a local m-resolvings of Wn and S be a local m-resolving set of Amal (Wn, v, m) Based on Lemma 0.2 that mdl (Amal(Wn, v, m)) ≤ m.mdl (Wn). Furthermore, we will show that mdl (Amal(Wn, v, m)) ≥ m.mdl (Wn). Take any SV (Amal (Wn, v, m)) with |P|<|S|. Suppose |P|=|S| − 1 = m.|W| − 1. There is one copy of Wn, (Wn)k have |Wk|− 1, such that we have three condition as follows

  • i For n ≡ 0(mod4)

    Let u(k, l) ∉ P for 1 ≤ ln or i ≡ 4s − 3 with 1sn4 and d (uk, 4(s−1)−3, u4(s+1)−3) > 4, then rmuk,4s11Wk==rmu4s+15Wk=2,2,2,,2n44. Since duk,4s11w==duk,4s+15w for wPWk and rmuk,4s11P==rmuk,4s+15P, then P is not local m-resolving set of Amal(Wn, v, m).

  • ii For n ≡ 2(mod4)

    There are three possibilities namely 1) uk,1P; 2) uk,lP for 1 < l < n − 1 and 3) uk,n−1P.

    • (a) Let uk,1P, then rmuk,1Wk==rmuk,3Wk=2,2,2,,2n41. Since duk,1w==duk,3w for wPWk and rmuk,1P==rmuk,3P, then P is not local m-resolving set of Amal (Wn, v, m).

    • (b) Let uk,lP for 1 < l < n − 1 or i ≡ 4s − 3 with 2kn41 and d (uk, 4(s−1)−3, uk, 4(s+1)−3) > 4, then rmuk,4s11Wk==rmuk,4s+15Wk=2,2,2,,2n41. Since duk,4s11w==duk,4s+15w for wPWk and rmuk,4s11P==rmuk,4s+15P, then P is not local m-resolving set of Amal (Wn, v, m).

    • (c) Let uk,n−1P. Since rmuk,n3Wk==rmuk,n1Wk=2,2,2,,2n41. Since duk,n3w==duk,n1w for wPWk and rmuk,n3P==rmuk,n1P, then P is not local m-resolving set of Amal (Wn, v, m).

  • iii For n ≡ 1, 3(mod4)

    We know that mdlWn=, so there are two adjacent vertices x, yV (Wn), rm(x|Wk) = rm(y|Wk). Since d(x, v) = d(y, v) and d(x, w) = d(x, w) where wPWk, then rm(x|P) = rm(y|P). Thus, mdlAmalWnvm=.

Based on i), ii), and iii) that mdl (Amal (Wn, v, m)) = m.mdl (Wn). □

For further discussion, consider graph Amal (Wn, v, m) where v is not a center vertex of Wn. Let V (Amal (Wn, v, m)) = {v} ∪ {uj;1 ≤ jm} ∪ {uj, i;1 ≤ jm and 1 ≤ in − 1} such that E (Amal(Wn, v, m)) = {vuj, vuj,1, vuj,n−1}∪{uj, iuj, i+1;1 ≤ in−2}∪{ujuj, i;1 ≤ jm, 1 ≤ in−1}.

Theorem 0.6

Let m and n be two integers with m ≥ 2 and n ≥ 3. Let Wn be a wheel graph of order n + 1 and vV (Wn) where v is not center vertex of Wn, then

mdlAmalWnvm=m.n41,forn0mod4m.n4,forn1,2,3mod4

Proof.

We consider four cases.

Case 1.

For n ≡ 0(mod 4)

Choose S = {uj,i;1 ≤ jm, 1 ≤ in − 1, i ≡ 0(mod4)} obtained the vertex representation as follows

  • 1. For uk, vV (Amal (Wn, v, m)), d(v, w)≠d (uk, w) where wSWk such that rm(v|SWk)≠rm (uk|SWk). Since d(v, w)≠d (uk, w) where wWk such that rm(v|Wk)≠rm (uk|Wk). Thus, rm(v|S)≠rm (uk|S).

  • 2. For uk, uk,lV ((Wn)k) and l≠0(mod4). Since uk adjacent to w where wWk, such that rm (uk|Wk)≠rm (uk,l|Wk). Since d (uk, w)≠d (uk,l, w) where wSWk such that rm (uk|SWk)≠rm (uk,l|SWk) with l≠1, n − 1. Since d (uk, w) = d (uk,l, w) where wSWk such that rm (uk|SWk) = rm (uk,l|SWk) with l = 1, n − 1. Thus, rm(v|S)≠rm (uk|S).

  • 3. For uk, iV ((Wn)k) and 1 ≤ i ≤ 3. Since d (uk,1, w)≠d (uk,2, w) where wSWk and d (uk,1, w)≠d (uk,2, w) where wWk such that rm (uk,1|S)≠rm (uk,2|S). Since d (uk,2, w) = d (uk,3, w) where wSWk and d (uk,2, w)≠d (uk,3, w) where wWk such that rm (uk,2|S)≠rm (uk,3|S).

  • 4. For uk, iV ((Wn)k) and n − 3 ≤ in − 1. Since d (uk,n−1, w)≠d (uk,n−2, w) where wSWk and d (uk,n−1, w)≠d (uk,n−2, w) where wWk such that rm (uk,n−1|S)≠rm (uk,n−2|S). Since d (uk,n−2, w) = d (uk,n−3, w) where wSWk and d (uk,n−2, w)≠d (uk,n−3, w) where wWk such that rm (uk,n−2|S)≠rm (uk,n−3|S).

  • 5. For uk, iV ((Wn)k) where 4l + 1 ≤ i ≤ 4l + 3 and 1ln84. Since d (uk,4l+1, w)≠d (uk,4l+2, w) where wSWk and d (uk,4l+1, w)≠d (uk,4l+2, w) where wWk such that rm (uk,4l+1|S)≠rm (uk,4l+2|S). Since d (uk,4l+2, w) = d (uk,4l+3, w) where wSWk and d (uk,4l+2, w)≠d (uk,4l+3, w) where wWk such that rm (uk,4l+2|S)≠rm (uk, 4l+3|S).

Based on the representation above that every two adjacent vertices has distinct representations such that S is local m-resolving set and mdlAmalWnvmm.n41. Furthermore, proving that mmdlAmalWnvmm.n41. Taking any set PV (Amal (Wn, v, m)) with |P|=m.n411. Let u(k, l) ∉ P for l ≡ 4s with 1sn84 and d (uk, 4(s−1), uk,4(s+1)) > 4, then rmuk,4s1+2Wk==rmu4s+12Wk=2,2,2,,2n84. Since duk,4s1+2w==duk,4s+12w for wPWk and rmuk,4s1+2P==rmuk,4s+12P, then P is not local m-resolving set of Amal (Wn, v, m). Thus, mdlAmalWnvm=m.n41.

Case 2.

For n ≡ 1(mod 4)

Choose S = {uj, i;1 ≤ jm, 1 ≤ in − 1, i ≡ 0(mod4)} obtained the vertex representation as follows

  • 1. For uk, vV (Amal (Wn, v, m)), d(v, w)≠d (uk, w) where wSWk such that rm(v|SWk)≠rm (uk|SWk). Since d(v, w)≠d (uk, w) where wWk such that rm(v|Wk)≠rm (uk|Wk). Thus, rm(v|S)≠rm (uk|S).

  • 2. For uk, uk,lV ((Wn)k) and l≠0(mod4). Since uk adjacent to w where wWk, such that rm (uk|Wk)≠rm (uk,l|Wk). Since d (uk, w)≠d (uk,l, w) where wSWk such that rm (uk|SWk)≠rm (uk,l|SWk) with l≠1, n − 1. Since d (uk, w) = d (uk,l, w) where wSWk such that rm (uk|SWk) = rm (uk,l|SWk) with l = 1, n − 1. Thus, rm(v|S)≠rm (uk|S).

  • 3. For uk, iV ((Wn)k) and 1 ≤ i ≤ 3. Since d (uk,1, w)≠d (uk,2, w) where wSWk and d (uk,1, w)≠d (uk,2, w) where wWk such that rm (uk,1|S)≠rm (uk,2|S). Since d (uk,2, w) = d (uk,3, w) where wSWk and d (uk,2, w)≠d (uk,3, w) where wWk such that rm (uk,2|S)≠rm (uk,3|S).

  • 4. For uk, iV ((Wn)k) where 4l + 1 ≤ i ≤ 4l + 3 and 1ln54. Since d (uk,4l+1, w)≠d (uk,4l+2, w) where wSWk and d (uk,4l+1, w)≠d (uk,4l+2, w) where wWk such that rm (uk,4l+1|S)≠rm (uk,4l+2|S). Since d (uk,4l+2, w) = d (uk,4l+3, w) where wSWk and d (uk,4l+2, w)≠d (uk,4l+3, w) where wWk such that rm (uk,4l+2|S)≠rm (uk,4l+3|S).

Based on the representation above that every two adjacent vertices has distinct representation such that S is local m-resolving set and mdlAmalWnvmm.n14. Furthermore, proving that mmdlAmalWnvmm.n14. Taking any set PV (Amal (Wn, v, m)) with |P|=m.n141. Let u(k, l) ∉ P for l ≡ 4s with 1sn54 and d (uk,4(s−1), uk,4(s+1)) > 4, then rmuk,4s1+2Wk==rmu4s+12Wk=2,2,2,,2n54. Since duk,4s1+2w==duk,4s+12w for wPWk and rmuk,4s1+2P==rmuk,4s+12P, then P is not local m-resolving set of Amal (Wn, v, m). Thus, mdlAmalWnvm=m.n14

Case 3.

For n ≡ 2(mod 4)

Choose S = {uj, i;1 ≤ jm, 1 ≤ in − 1, i ≡ 0(mod4)} obtained the vertex representation as follows

  • 1. For uk, vV (Amal (Wn, v, m)), d(v, w)≠d (uk, w) where wSWk such that rm(v|SWk)≠rm (uk|SWk). Since d(v, w)≠d (uk, w) where wWk such that rm(v|Wk)≠rm (uk|Wk). Thus, rm(v|S)≠rm (uk|S).

  • 2. For uk, uk,lV ((Wn)k) and l≠0(mod4). Since uk adjacent to w where wWk, such that rm (uk|Wk)≠rm (uk,l|Wk). Since d (uk, w)≠d (uk,l, w) where wSWk such that rm (uk|SWk)≠rm (uk,l|SWk) with l≠1, n − 1. Since d (uk, w) = d (uk,l, w) where wSWk such that rm (uk|SWk) = rm (uk,l|SWk) with l = 1, n − 1. Thus, rm(v|S)≠rm (uk|S).

  • 3. For uk,iV ((Wn)k) and 1 ≤ i ≤ 3. Since d (uk,1, w)≠d (uk,2, w) where wSWk and d (uk,1, w)≠d (uk,2, w) where wWk such that rm (uk,1|S)≠rm (uk,2|S). Since d (uk,2, w) = d (uk,3, w) where wSWk and d (uk,2, w)≠d (uk,3, w) where wWk such that rm (uk,2|S)≠rm (uk,3|S).

  • 4. For uk, iV ((Wn)k) where 4l + 1 ≤ i ≤ 4l + 3 and 1ln64. Since d (uk,4l+1, w)≠d (uk,4l+2, w) where wSWk and d (uk,4l+1, w)≠d (uk,4l+2, w) where wWk such that rm (uk,4l+1|S)≠rm (uk,4l+2|S). Since d (uk,4l+2, w) = d (uk,4l+3, w) where wSWk and d (uk,4l+2, w)≠d (uk,4l+3, w) where wWk such that rm (uk,4l+2|S)≠rm (uk,4l+3|S).

Based on the representation above that every two adjacent vertices has distinct representation such that S is local m-resolving set and mdlAmalWnvmm.n24. Furthermore, proving that mmdlAmalWnvmm.n24. Taking any set PV (Amal (Wn, v, m)) with |P|=m.n241. Let u(k, l) ∉ P for l ≡ 4s with 1sn64 and d (uk,4(s−1), uk,4(s+1)) > 4, then rmuk,4s1+2Wk==rmu4s+12Wk=2,2,2,,2n64. Since duk,4s1+2w==duk,4s+12w for wPWk and rmuk,4s1+2P==rmuk,4s+12P, then P is not local m-resolving set of Amal (Wn, v, m). Thus, mdlAmalWnvm=m.n24

Case 4.

For n ≡ 3(mod 4)

Choose S = {uj, i;1 ≤ jm, 1 ≤ in − 1, i ≡ 0(mod4)} obtained the vertex representation as follows

  • 1. For uk, vV (Amal (Wn, v, m)), d(v, w)≠d (uk, w) where wSWk such that rm(v|SWk)≠rm (uk|SWk). Since d(v, w)≠d (uk, w) where wWk such that rm(v|Wk)≠rm (uk|Wk). Thus, rm(v|S)≠rm (uk|S).

  • 2. For uk, uk,lV ((Wn)k) and l≠0(mod4). Since uk adjacent to w where wWk, such that rm (uk|Wk)≠rm (uk,l|Wk). Since d (uk, w)≠d (uk,l, w) where wSWk such that rm (uk|SWk)≠rm (uk,l|SWk) with l≠1, n − 1. Since d (uk, w) = d (uk,l, w) where wSWk such that rm (uk|SWk) = rm (uk,l|SWk) with l = 1, n − 1. Thus, rm(v|S)≠rm (uk|S).

  • 3. For uk, iV ((Wn)k) and 1 ≤ i ≤ 3. Since d (uk,1, w)≠d (uk,2, w) where wSWk and d (uk,1, w)≠d (uk,2, w) where wWk such that rm (uk,1|S)≠rm (uk,2|S). Since d (uk,2, w) = d (uk,3, w) where wSWk and d (uk,2, w)≠d (uk,3, w) where wWk such that rm (uk,2|S)≠rm (uk,3|S).

  • 4. For uk, iV ((Wn)k) and n − 2 ≤ in − 1. Since d (uk,n−1, w)≠d (uk,n−2, w) where wSWk and d (uk,n−1, w)≠d (uk,n−2, w) where wWk such that rm (uk,n−1|S)≠rm (uk,n−2|S).

  • 5. For uk, iV ((Wn)k) where 4l + 1 ≤ i ≤ 4l + 3 and 1ln74. Since d (uk,4l+1, w)≠d (uk,4l+2, w) where wSWk and d (uk,4l+1, w)≠d (uk,4l+2, w) where wWk such that rm (uk,4l+1|S)≠rm (uk,4l+2|S). Since d (uk,4l+2, w) = d (uk,4l+3, w) where wSWk and d (uk,4l+2, w)≠d (uk,4l+3, w) where wWk such that rm (uk,4l+2|S)≠rm (uk,4l+3|S).

Based on the representation above that every two adjacent vertices has distinct representations such that S is local m-resolving set and mdlAmalWnvmm.n34. Furthermore, proving that mmdlAmalWnvmm.n34. Taking any set PV (Amal (Wn, v, m)) with |P|=m.n341. Let u(k, l) ∉ P for l ≡ 4s with 1sn74 and d (uk, 4(s−1), uk, 4(s+1)) > 4, then rmuk,4s1+2Wk==rmu4s+12Wk=2,2,2,,2n74. Since duk,4s1+2w==duk,4s+12w for wPWk and rmuk,4s1+2P==rmuk,4s+12P, then P is not local m-resolving set of Amal (Wn, v, m). Thus, mdlAmalWnvm=m.n34. □

Consider graph Amal (Fn, v, m) where v is a center vertex of Fn. Let V (Amal (Fn, v, m)) = {v} ∪ {uj, i;1 ≤ jmand1 ≤ in} such that EAmalFnvm=j=1j=mEFnj.

Theorem 0.7

Let m and n be two integers with m ≥ 2 and n ≥ 6. Let Fn be a fan graph of order n + 1 and vV (Fn) where v is a center vertex of Fn, then mdl (Amal (Fn, v, m)) = m.mdl (Fn)

Proof.

Let W be a local m-resolvings of Fn and S be a local m-resolving set of Amal (Fn, v, m) Based on Lemma 0.2 that mdl (Amal(Fn, v, m)) ≤ m.mdl (Fn). Furthermore, we will show that mdl (Amal(Fn, v, m)) ≥ m.mdl (Fn). Take any SV (Amal (Fn, v, m)) with |P|<|S|. Suppose |P|=|S| − 1 = m.|W| − 1. There are one copies of Fn, (Fn)k have |Wk|− 1, such that we have three condition as follows

  • i For n ≡ 1(mod4)

    There are three possibilities namely 1) uk,3P; 2) uk,lP for 3 < l < n − 2 and 3) uk,n−2P.

    • (a) Let uk,3P. Since uk,1uk,2E((Fn)k), then rmuk,1Wk=rmuk,2Wk=2,2,2,,2n54. Since d (uk,1, w) = d (uk,2, w) for wPWk and rm (uk,1|P) = rm (uk,2|P), then P is not local m-resolving set of Amal (Fn, v, m).

    • (b) Let uk,lP for 3 < l < n − 2 or i ≡ 4s − 1 with 2sn54 and d (uk, 4(s−1)−1, uk, 4(s+1)−1) > 4, then rmuk,4s1+1Wk==rmuk,4s+13Wk=2,2,2,,2n54. Since duk,4s1+1w==duk,4s+13w for wPWk and rmuk,4s1+1P==rmuk,4s+13P, then P is not local m-resolving set of Amal (Fn, v, m).

    • (c) Let uk,n−2P. Since uk,n−1uk, nE((Fn)k), then rmuk,n4Wk==rmuk,nWk=2,2,2,,2n54. Since duk,n4w==duk,nw for wPWk and rmuk,n4P==rmuk,nP, then P is not local m-resolving set of Amal (Fn, v, m).

  • ii For n ≡ 0, 2, 3(mod4)

    There are three possibilities namely 1) uk,1P; 2) uk,lP for 1 < l < n − 1 and 3) uk,n−1P for n ≡ 0(mod4), uk,n−1P for n ≡ 2(mod4), and uk,nP for n ≡ 3(mod4).

    • (a) Let uk,3P. Since rmuk,1Wk==rmuk,5Wk=2,2,2,,2n41. Since duk,1w==duk,5w for wPWk and rmuk,1P==rmuk,5P, then P is not local m-resolving set of Amal (Fn, v, m).

    • (b) Let uk,lP for 3 < l < n − 2 or i ≡ 4s − 1 with 2sn4 and d (uk,4(s−1)−1, uk, 4(s+1)−1) > 4, then rmuk,4s1+1Wk==rmuk,4s+13Wk=2,2,2,,2n41. Since duk,4s1+1w==duk,4s+13w for wPWk and rmuk,4s1+1P==rmuk,4s+13P, then P is not local m-resolving set of Amal (Fn, v, m).

    • (c) Let uk,n−1P for n ≡ 0(mod4). Since rmuk,n3Wk==rmuk,nWk=2,2,2,,2n41. Since duk,n3w==duk,nw for wPWk and rmuk,n3P==rmuk,nP, then P is not local m-resolving set of Amal (Fn, v, m).

    • (d) Let uk,n−1P for n ≡ 2(mod4). Since rmuk,n1Wk=rmuk,nWk=2,2,2,,2n41. Since d (uk,n−1, w) = d (uk,n, w) for wPWk and rm (uk,n−1|P) = rm (uk,n|P), then P is not local m-resolving set of Amal (Fn, v, m).

    • (e) Let uk,nP for n ≡ 3(mod4). Since rmuk,n2Wk==rmuk,nWk=2,2,2,,2n41. Since duk,n2w==duk,nw for wPWk and rmuk,n2P==rmuk,nP, then P is not local m-resolving set of Amal (Fn, v, m).

Based on i) and ii) that mdl (Amal (Fn, v, m)) = m.mdl (Fn). □

For further discussion, consider graph Amal (Fn, v, m) where vV (Fn) with d(v) = 2. Let V (Amal (Fn, v, m)) = {v} ∪ {uj;1 ≤ jm} ∪ {uj, i;1 ≤ jmand1 ≤ in − 1} such that E (Amal(Fn, v, m)) = {vuj, vuj,1}∪{uj, iuj, i+1;1 ≤ in−2}∪{ujuj, i;1 ≤ jm, 1 ≤ in−1}.

Theorem 0.8

Let m and n be two integers with m ≥ 2 and n ≥ 3. Let Fn be a fan graph of order n + 1 and vV (Fn) where d(v) = 2, then mdlAmalFnvm=m.n4

Proof.

We have some condition for the set S as follows

  • a for n ≡ 1, 2, 3(mod4), S = {uj, i;1 ≤ jm, 1 ≤ in − 1, i ≡ 0(mod4)}.

  • b for n ≡ 0(mod4), S = {uj, i;1 ≤ jm, 1 ≤ in − 1, i ≡ 0(mod4)} ∪ {uj,n−2}.

We obtained the vertex representation as follows

  • 1. For uk, vV (Amal (Fn, v, m)), d(v, w)≠d (uk, w) where wSWk such that rm(v|SWk)≠rm (uk|SWk). Since d(v, w)≠d (uk, w) where wWk such that rm(v|Wk)≠rm (uk|Wk). Thus, rm(v|S)≠rm (uk|S).

  • 2. For uk, uk,lV ((Fn)k) where l≠0(mod4) and uk,l where ln − 2 for n ≡ 0(mod4). Since uk is adjacent to w where wWk, such that rm (uk|Wk)≠rm (uk,l|Wk). Since d (uk, w)≠d (uk,l, w) where wSWk such that rm (uk|SWk)≠rm (uk,l|SWk) with l≠1. Since d (uk, w) = d (uk,l, w) where wSWk such that rm (uk|SWk) = rm (uk,l|SWk) with l = 1. Thus, rm(v|S)≠rm (uk|S).

  • 3. For uk, iV ((Fn)k) and 1 ≤ i ≤ 3. Since d (uk,1, w)≠d (uk,2, w) where wSWk and d (uk,1, w)≠d (uk,2, w) where wWk such that rm (uk,1|S)≠rm (uk,2|S). Since d (uk,2, w) = d (uk,3, w) where wSWk and d (uk,2, w)≠d (uk,3, w) where wWk such that rm (uk,2|S)≠rm (uk,3|S).

  • 4. For uk, iV ((Fn)k) where 4l + 1 ≤ i ≤ 4l + 3 and 1ln41. Since d (uk,4l+1, w)≠d (uk,4l+2, w) where wSWk and d (uk,4l+1, w)≠d (uk,4l+2, w) where wWk such that rm (uk,4l+1|S)≠rm (uk,4l+2|S). Since d (uk,4l+2, w) = d (uk,4l+3, w) where wSWk and d (uk,4l+2, w)≠d (uk,4l+3, w) where wWk such that rm (uk,4l+2|S)≠rm (uk,4l+3|S).

  • 5. For uk, iV ((Fn)k) where n − 2 ≤ in − 1 and n ≡ 3(mod4). Since d (uk,n−1, w) = d (uk,n−2, w) where wSWk and d (uk,n−1, w)≠d (uk,n−2, w) where wWk such that rm (uk,n−1|S)≠rm (uk,n−2|S).

Based on the representation above that every two adjacent vertices has distinct representations such that S is local m-resolving set and mdlAmalWnvmm.n41.

Furthermore, we will show that mdlAmalFnvmm.n4. Take any SV (Amal (Fn, v, m)) with|P|<|S|. Suppose |P|=|S|1=m.n41. There are one copies of Fn, (Fn)k have n41, such that we have three condition as follows

  • i For n ≡ 1(mod4)

    There are three possibilities namely 1) uk,lP for 1 < l < n − 1 and 2) uk,n−1P.

    • (a) Let uk,lP for 1 < ln − 1 or l ≡ 4s with 1sn54 and d (uk, 4(s−1)+1, uk, 4(s+1)−1) > 4, then rmuk,4s1+2Wk==rmuk,4s+12Wk=2,2,2,,2n54. Since duk,4s1+2w==duk,4s+12w for wPWk and rmuk,4s1+2P==rmuk,4s+12P, then P is not local m-resolving set of Amal (Fn, v, m).

    • (b) Let uk,n−1P. Since rmuk,n3Wk==rmuk,n1Wk=2,2,2,,2n54. Since duk,n3w==duk,n1w for wPWk and rmuk,n3P==rmuk,n1P, then P is not local m-resolving set of Amal (Fn, v, m).

  • ii For n ≡ 0, 2, 3(mod4)

    There are three possibilities namely 1) uk,lP for 1 < l < n − 1 and 2) uk,n−1P for n ≡ 0(mod4), uk,n−2P for n ≡ 2(mod4), and uk,n−3P for n ≡ 3(mod4).

    • (a) Let uk,lP for 1 < l < n − 1 or l ≡ 4s with 1sn41 and d (uk, 4(s−1)+1, uk, 4(s+1)−1) > 4, then rmuk,4s1+2Wk==rmuk,4s+12Wk=2,2,2,,2n41. Since duk,4s1+2w==duk,4s+12w for wPWk and rmuk,4s1+2P==rmuk,4s+12P, then P is not local m-resolving set of Amal (Fn, v, m).

    • (b) Let uk,n−1P for n ≡ 0(mod4). Since rmuk,n2Wk=rmuk,n1Wk=2,2,2,,2n41. Since d (uk,n−2, w) = d (uk,n−1, w) for wPWk and rm (uk,n−2|P) = rm (uk,n−1|P), then P is not local m-resolving set of Amal (Fn, v, m).

    • (c) Let uk,n−2P for n ≡ 2(mod4). Since rmuk,n4Wk==rmuk,n1Wk=2,2,2,,2n41. Since duk,n4w==duk,n1w for wPWk and rmuk,n4P==rmuk,n1P, then P is not local m-resolving set of Amal (Fn, v, m).

    • (d) Let uk,n−3P for n ≡ 3(mod4). Since rmuk,n5Wk==rmuk,n1Wk=2,2,2,,2n41. Since duk,n5w==duk,n1w for wPWk and rmuk,n5P==rmuk,n1P, then P is not local m-resolving set of Amal (Fn, v, m).

Based on i) and ii) that mdlAmalFnvm=m.n4. □

Theorem 0.9

Let m and n be two integers with m ≥ 2 and n ≥ 3. Let Fn be a fan graph of order n + 1 and vV (Fn) where d(v) = 3, then

mdlAmalFnvm=m.p4+np4,fornp0,1,2mod4and2pn4m.p4+np4,fornp3mod4and2pn4

Proof.

Since Identified vertex v = uj, p, then we have two part namely uj,1uj, p−1 and uj, p+1uj, n. We consider two cases as follows

Case 1.

For 2 ≤ p ≤ 3

For d (uj,1, uj, p−1) ≤ 2, then the vertices uj,1,,uj,p1 don’t need to be resolver. Thus, we focus for d (uj, p+1, uj, n) ≥ 3

Sub Case 1.1.

For np ≡ 0, 1, 2(mod4)

Choose S = {uj,r;1 ≤ jm, rp (mod4), r > p} obtained the vertex representation as follows

  • 1. For uk,lV (Amal (Fn, v, m)) and 1 ≤ lp − 1, d (uk,1, w)≠d (uk,2, w) where wSWk such that rm (uk,1|SWk)≠rm (uk,2|SWk). Since d (uk,1, w) = d (uk,2, w) where wWk such that rm (uk,1|Wk)≠rm (uk,2|Wk). Thus, rm (uk,1|S)≠rm (uk,2|S).

  • 2. For uk, vV (Amal (Fn, v, m)), d(v, w)≠d (uk, w) where wSWk such that rm(v|SWk)≠rm (uk|SWk). Since d(v, w)≠d (uk, w) where wWk such that rm(v|Wk)≠rm (uk|Wk). Thus, rm(v|S)≠rm (uk|S).

  • 3. For uk, uk,lV ((Fn)k) where lp (mod4) and uk,l where ln − 2 for np ≡ 2(mod4). Since uk adjacent to w where wWk, such that rm (uk|Wk)≠rm (uk,l|Wk). Since d (uk, w)≠d (uk,l, w) where wSWk such that rm (uk|SWk)≠rm (uk,l|SWk) with l≠1. Since d (uk, w) = d (uk,l, w) where wSWk such that rm (uk|SWk) = rm (uk,l|SWk) with l = 1. Thus, rm(v|S)≠rm (uk|S).

  • 4. For uk, iV ((Fn)k) and p + 1 ≤ ip + 3. Since d (uk, p+1, w)≠d (uk, p+2, w) where wSWk and d (uk, p+1, w)≠d (uk, p+2, w) where wWk such that rm (uk, p+1|S)≠rm (uk, p+2|S). Since d (uk, p+2, w) = d (uk, p+3, w) where wSWk and d (uk, p+2, w)≠d (uk, p+3, w) where wWk such that rm (uk, p+2|S)≠rm (uk, p+3|S).

  • 5. For uk, iV ((Fn)k) where p + 4l + 1 ≤ ip + 4l + 3 and 1ln41. Since d (uk, p+4l+1, w)≠d (uk, p+4l+2, w) where wSWk and d (uk, p+4l+1, w)≠d (uk, p+4l+2, w) where wWk such that rm (uk, p+4l+1|S)≠rm (uk, p+4l+2|S). Since d (uk, p+4l+2, w) = d (uk, p+4l+3, w) where wSWk and d (uk, p+4l+2, w)≠d (uk, p+4l+3, w) where wWk such that rm (uk, p+4l+2|S)≠rm (uk, p+4l+3|S).

Based on the representation above that every two adjacent vertices have distinct representations such that S is local m-resolving set and mdlAmalFnvmm.p4+np4.

Furthermore, we will show that mdlAmalFnvmm.p4+np4. Take any SV (Amal (Fn, v, m)) with |P|<|S|. Suppose |P|=|S|1=m.p4+np41. There is one copy of Fn, (Fn)k have m.p4+np41. Let uk,lP for p + 1 < ln − 1 or lp + 4s with 1snp4 and d (uk, p+4(s−1)+1, uk, p+4(s+1)−1) > 4, then rmuk,p+4s1+2Wk==rmuk,p+4s+12Wk=2,2,2,,2np41. Since duk,p+4s1+2w==duk,p+4s+12w for wPWk and rmuk,p+4s1+2P==rmuk,p+4s+12P, then P is not local m-resolving set of Amal (Fn, v, m). Thus, mdlAmalFnvm=m.p4+np4.

Sub Case 1.2.

For np ≡ 3(mod4)

Choose S = {uj,r;1 ≤ jm, rp (mod4), r > p} ∪ {uj,n−1} obtained the vertex representation as follows

  • 1. For uk,lV (Amal (Fn, v, m)) and 1 ≤ lp − 1, d (uk,1, w)≠d (uk,2, w) where wSWk such that rm (uk,1|SWk)≠rm (uk,2|SWk). Since d (uk,1, w) = d (uk,2, w) where wWk such that rm (uk,1|Wk)≠rm (uk,2|Wk). Thus, rm (uk,1|S)≠rm (uk,2|S).

  • 2. For uk, vV (Amal (Fn, v, m)), d(v, w)≠d (uk, w) where wSWk such that rm(v|SWk)≠rm (uk|SWk). Since d(v, w)≠d (uk, w) where wWk such that rm(v|Wk)≠rm (uk|Wk). Thus, rm(v|S)≠rm (uk|S).

  • 3. For uk, uk,lV ((Fn)k) where lp (mod4) and uk,l where ln − 2 for np ≡ 3(mod4). Since uk adjacent to w where wWk, such that rm (uk|Wk)≠rm (uk,l|Wk). Since d (uk, w)≠d (uk,l, w) where wSWk such that rm (uk|SWk)≠rm (uk,l|SWk) with l≠1. Since d (uk, w) = d (uk,l, w) where wSWk such that rm (uk|SWk) = rm (uk,l|SWk) with l = 1. Thus, rm(v|S)≠rm (uk|S).

  • 4. For uk, iV ((Fn)k) and p + 1 ≤ ip + 3. Since d (uk, p+1, w)≠d (uk, p+2, w) where wSWk and d (uk, p+1, w)≠d (uk, p+2, w) where wWk such that rm (uk, p+1|S)≠rm (uk, p+2|S). Since d (uk, p+2, w) = d (uk, p+3, w) where wSWk and d (uk, p+2, w)≠d (uk, p+3, w) where wWk such that rm (uk, p+2|S)≠rm (uk, p+3|S).

  • 5. For uk, iV ((Fn)k) where p + 4l + 1 ≤ ip + 4l + 3 and 1ln41. Since d (uk, p+4l+1, w)≠d (uk, p+4l+2, w) where wSWk and d (uk, p+4l+1, w)≠d (uk, p+4l+2, w) where wWk such that rm (uk, p+4l+1|S)≠rm (uk, p+4l+2|S). Since d (uk, p+4l+2, w) = d (uk, p+4l+3, w) where wSWk and d (uk, p+4l+2, w)≠d (uk, p+4l+3, w) where wWk such that rm (uk, p+4l+2|S)≠rm (uk, p+4l+3|S).

  • 6. For uk, iV ((Fn)k) where i = n − 2, n. Since uk,n−2 is not adjacent to uk, n. It is clear.

Based on the representation above that every two adjacent vertices has distinct representations such that S is local m-resolving set and mdlAmalFnvmm.p4+np4.

Furthermore, we will show that mdlAmalFnvmm.p4+np4. Take any SV (Amal (Fn, v, m)) with|P|<|S|. Suppose |P|=|S|1=m.p4+np41. There are one copies of Fn, (Fn)k have m.p4+np41. There are three possibilities namely 1) uk,lP for 1 < l < n − 1 and 2) uk,n−1P.

  • 1. Let uk,lP for 1 < ln − 1 or lp + 4s with 1snp4 and d (uk, p+4(s−1)+1, uk, p+4(s+1)−1) > 4, then rmuk,p+4s1+2Wk==rmuk,p+4s+12Wk=2,2,2,,2np4. Since duk,p+4s1+2w==duk,p+4s+12w for wPWk and rmuk,p+4s1+2P==rmuk,p+4s+12P, then P is not local m-resolving set of Amal (Fn, v, m).

  • 2. Let uk,n−1P. Since rmuk,n1Wk=rmuk,nWk=2,2,2,,2np4. Since d (uk,n−1, w) = d (uk, n, w) for wPWk and rm (uk,n−1|P) = rm (uk, n|P), then P is not local m-resolving set of Amal (Fn, v, m).

Based on 1) and 2) that mdlAmalFnvmm.p4+np4. Thus, mdlAmalFnvm=m.p4+np4.

Case 2.

For 4pn4

Sub Case 2.1.

For np ≡ 0, 1, 2(mod4)

We have some conditions for the set S as follows:

  • a for p ≡ 1(mod4), S = {uj, t;1 ≤ jm, t ≡ 1(mod4)} ∪ {uj,r;1 ≤ jm, rp (mod4), r > p}.

  • b for p ≡ 2(mod4), S = {uj, t;1 ≤ jm, t ≡ 2(mod4)} ∪ {uj,r;1 ≤ jm, rp (mod4), r > p}.

  • c for p ≡ 3(mod4), S = {uj, t;1 ≤ jm, t ≡ 3(mod4)} ∪ {uj,r;1 ≤ jm, rp (mod4), r > p}.

  • d for p ≡ 0(mod4), S = {uj, t;1 ≤ jm, t ≡ 0(mod4)} ∪ {uj,r;1 ≤ jm, rp (mod4), r > p}.

We obtained the vertex representation as follows:

  • 1. For uk, iV ((Fn)k) where p − 3 ≤ ip − 1 and p ≡ 0, 1, 2, 3(mod4). Since d (uk, p−1, w)≠d (uk, p−2, w) where wSWk and d (uk, p−1, w)≠d (uk, p−2, w) where wWk such that rm (uk, p−1|S)≠rm (uk, p−2|S). Since d (uk, p−2, w) = d (uk, p−3, w) where wSWk and d (uk, p−2, w)≠d (uk, p−3, w) where wWk such that rm (uk, p−2|S)≠rm (uk, p−3|S).

  • 2. For uk, iV ((Fn)k) where p − 4l + 1 ≤ ip − 4l + 3, 2ln41, and ap ≡ 0, 1, 2, 3(mod4). Since d (uk, p−4l+1, w)≠d (uk, p−4l+2, w) where wSWk and d (uk, p−4l+1, w)≠d (uk, p−4l+2, w) where wWk such that rm (uk, p−4l+1|S)≠rm (uk, p−4l+2|S). Since d (uk, p−4l+2, w) = d (uk, p−4l+3, w) where wSWk and d (uk, p−4l+2, w)≠d (uk, p−4l+3, w) where wWk such that rm (uk, p−4l+2|S)≠rm (uk, p−4l+3|S).

  • 3. For uk,lV (Amal (Fn, v, m)) and 1 ≤ lp − 1, d (uk,1, w)≠d (uk,2, w) where wSWk such that rm (uk,1|SWk)≠rm (uk,2|SWk). Since d (uk,1, w) = d (uk,2, w) where wWk such that rm (uk,1|Wk)≠rm (uk,2|Wk). Thus, rm (uk,1|S)≠rm (uk,2|S).

  • 4. For uk, vV (Amal (Fn, v, m)), d(v, w)≠d (uk, w) where wSWk such that rm(v|SWk)≠rm (uk|SWk). Since d(v, w)≠d (uk, w) where wWk such that rm(v|Wk)≠rm (uk|Wk). Thus, rm(v|S)≠rm (uk|S).

  • 5. For uk, uk,lV ((Fn)k) where lp (mod4) and uk,l where ln − 2 for np ≡ 2(mod4). Since uk adjacent to w where wWk, such that rm (uk|Wk)≠rm (uk,l|Wk). Since d (uk, w)≠d (uk,l, w) where wSWk such that rm (uk|SWk)≠rm (uk,l|SWk) with l≠1. Since d (uk, w) = d (uk,l, w) where wSWk such that rm (uk|SWk) = rm (uk,l|SWk) with l = 1. Thus, rm(v|S)≠rm (uk|S).

  • 6. For uk, iV ((Fn)k) and p + 1 ≤ ip + 3. Since d (uk, p+1, w)≠d (uk, p+2, w) where wSWk and d (uk, p+1, w)≠d (uk, p+2, w) where wWk such that rm (uk, p+1|S)≠rm (uk, p+2|S). Since d (uk, p+2, w) = d (uk, p+3, w) where wSWk and d (uk, p+2, w)≠d (uk, p+3, w) where wWk such that rm (uk, p+2|S)≠rm (uk, p+3|S).

  • 7. For uk, iV ((Fn)k) where p + 4l + 1 ≤ ip + 4l + 3 and 1ln41. Since d (uk, p+4l+1, w)≠d (uk, p+4l+2, w) where wSWk and d (uk, p+4l+1, w)≠d (uk, p+4l+2, w) where wWk such that rm (uk, p+4l+1|S)≠rm (uk, p+4l+2|S). Since d (uk, p+4l+2, w) = d (uk, p+4l+3, w) where wSWk and d (uk, p+4l+2, w)≠d (uk, p+4l+3, w) where wWk such that rm (uk, p+4l+2|S)≠rm (uk, p+4l+3|S).

Based on the representation above that every two adjacent vertices has distinct representations such that S is a local m-resolving set and mdlAmalFnvmm.p4+np4.

Furthermore, we will show that mdlAmalFnvmm.p4+np4. Take any SV (Amal (Fn, v, m)) with|P|<|S|. Suppose |P|=|S|1=m.p4+np41. There are one copies of Fn, (Fn)k have m.p4+np41.

  • 1. Let uk,lP for p + 1 < ln − 1 or lp + 4s with 1snp4 and d (uk, p+4(s−1)+1, uk, p+4(s+1)−1) > 4, then rmuk,p+4s1+2Wk==rmuk,p+4s+12Wk=2,2,2,,2np41. Since duk,p+4s1+2w==duk,p+4s+12w for wPWk and rmuk,p+4s1+2P==rmuk,p+4s+12P, then P is not local m-resolving set of Amal (Fn, v, m).

  • 2. Let uk,lP for 1 < lp − 1 or l ≡ 1(mod4) and p ≡ 1(mod4), then rmuk,p4s2Wk==rmuk,p4s+2Wk=2,2,2,,2np41. Since duk,p4s2w==duk,p4s+2w for wPWk and rmuk,p4s2P==rmuk,p4s+2P, then P is not local m-resolving set of Amal (Fn, v, m).

Thus, mdlAmalFnvm=m.p4+np4.

Sub Case 2.2.

For np ≡ 3(mod4)

We have some conditions for the set S as follows

  • a for p ≡ 1(mod4), S = {uj, t;1 ≤ jm, t ≡ 1(mod4)}∪{uj,r;1 ≤ jm, rp (mod4), r > p}∪{uj,n−1}.

  • b for p ≡ 2(mod4), S = {uj, t;1 ≤ jm, t ≡ 2(mod4)}∪{uj,r;1 ≤ jm, rp (mod4), r > p}∪{uj,n−1}.

  • c for p ≡ 3(mod4), S = {uj, t;1 ≤ jm, t ≡ 3(mod4)}∪{uj,r;1 ≤ jm, rp (mod4), r > p}∪{uj,n−1}.

  • d for p ≡ 0(mod4), S = {uj, t;1 ≤ jm, t ≡ 0(mod4)}∪{uj,r;1 ≤ jm, rp (mod4), r > p}∪{uj,n−1}.

We obtained the vertex representation as follows:

  • 1. For uk, iV ((Fn)k) where p − 3 ≤ ip − 1 and p ≡ 0, 1, 2, 3(mod4). Since d (uk, p−1, w)≠d (uk, p−2, w) where wSWk and d (uk, p−1, w)≠d (uk, p−2, w) where wWk such that rm (uk, p−1|S)≠rm (uk, p−2|S). Since d (uk, p−2, w) = d (uk, p−3, w) where wSWk and d (uk, p−2, w)≠d (uk, p−3, w) where wWk such that rm (uk, p−2|S)≠rm (uk, p−3|S).

  • 2. For uk, iV ((Fn)k) where p − 4l + 1 ≤ ip − 4l + 3, 2ln41, and ap ≡ 0, 1, 2, 3(mod4). Since d (uk,p−4l+1, w)≠d (uk, p−4l+2, w) where wSWk and d (uk, p−4l+1, w)≠d (uk, p−4l+2, w) where wWk such that rm (uk, p−4l+1|S)≠rm (uk, p−4l+2|S). Since d (uk, p−4l+2, w) = d (uk, p−4l+3, w) where wSWk and d (uk, p−4l+2,w)≠d (uk, p−4l+3, w) where wWk such that rm (uk, p−4l+2|S)≠rm (uk, p−4l+3|S).

  • 3. For uk,lV (Amal (Fn, v, m)) and 1 ≤ lp − 1, d (uk,1, w)≠d (uk,2, w) where wSWk such that rm (uk,1|SWk)≠rm (uk,2|SWk). Since d (uk,1, w) = d (uk,2, w) where wWk such that rm (uk,1|Wk)≠rm (uk,2|Wk). Thus, rm (uk,1|S)≠rm (uk,2|S).

  • 4. For uk, vV (Amal (Fn, v, m)), d(v, w)≠d (uk, w) where wSWk such that rm(v|SWk)≠rm (uk|SWk). Since d(v, w)≠d (uk, w) where wWk such that rm(v|Wk)≠rm (uk|Wk). Thus, rm(v|S)≠rm (uk|S).

  • 5. For uk, uk,lV ((Fn)k) where lp (mod4) and uk,l where ln − 2 for np ≡ 3(mod4). Since uk adjacent to w where wWk, such that rm (uk|Wk)≠rm (uk,l|Wk). Since d (uk, w)≠d (uk,l, w) where wSWk such that rm (uk|SWk)≠rm (uk,l|SWk) with l≠1. Since d (uk, w) = d (uk,l, w) where wSWk such that rm (uk|SWk) = rm (uk,l|SWk) with l = 1. Thus, rm(v|S)≠rm (uk|S).

  • 6. For uk, iV ((Fn)k) and p + 1 ≤ ip + 3. Since d (uk, p+1, w)≠d (uk, p+2, w) where wSWk and d (uk, p+1, w)≠d (uk, p+2, w) where wWk such that rm (uk, p+1|S)≠rm (uk, p+2|S). Since d (uk, p+2, w) = d (uk, p+3, w) where wSWk and d (uk, p+2, w)≠d (uk, p+3, w) where wWk such that rm (uk, p+2|S)≠rm (uk, p+3|S).

  • 7. For uk, iV ((Fn)k) where p + 4l + 1 ≤ ip + 4l + 3 and 1ln41. Since d (uk, p+4l+1, w)≠d (uk, p+4l+2, w) where wSWk and d (uk, p+4l+1, w)≠d (uk, p+4l+2, w) where wWk such that rm (uk, p+4l+1|S)≠rm (uk, p+4l+2|S). Since d (uk, p+4l+2, w) = d (uk, p+4l+3, w) where wSWk and d (uk, p+4l+2, w)≠d (uk, p+4l+3, w) where wWk such that rm (uk, p+4l+2|S)≠rm (uk, p+4l+3|S).

  • 8. For uk, iV ((Fn)k) where i = n − 2, n. Since uk,n−2 does not adjacent to uk, n. It is clear.

Based on the representation above that every two adjacent vertices have distinct representations such that S is a local m-resolving set and mdlAmalFnvmm.p4+np4.

Furthermore, we will show that mdlAmalFnvmm.p4+np4. Take any SV (Amal (Fn, v, m)) with|P|<|S|. Suppose |P|=|S|1=m.p4+np41. There are one copies of Fn, (Fn)k have m.p4+np41. There are three possibilities namely 1) uk,lP for 1 < l < n − 1 and 2) uk,n−1P.

  • 1. Let uk,lP for 1 < ln − 1 or lp + 4s with 1snp4 and d (uk, p+4(s−1)+1, uk, p+4(s+1)−1) > 4, then rmuk,p+4s1+2Wk==rmuk,p+4s+12Wk=2,2,2,,2np4. Since duk,p+4s1+2w==duk,p+4s+12w for wPWk and rmuk,p+4s1+2P==rmuk,p+4s+12P, then P is not local m-resolving set of Amal (Fn, v, m).

  • 2. Let uk,n−1P. Since rmuk,n1Wk=rmuk,nWk=2,2,2,,2np4. Since d (uk,n−1, w) = d (uk, n, w) for wPWk and rm (uk,n−1|P) = rm (uk, n|P), then P is not local m-resolving set of Amal (Fn, v, m).

  • 3. Let uk,lP for 1 < lp − 1 or l ≡ 1(mod4) and p ≡ 1(mod4), then rmuk,p4s2Wk==rmuk,p4s+2Wk=2,2,2,,2np41. Since duk,p4s2w==duk,p4s+2w for wPWk and rmuk,p4s2P==rmuk,p4s+2P, then P is not local m-resolving set of Amal (Fn, v, m).

Based on 1) and 2) that mdlAmalFnvmm.p4+np4. Thus, mdlAmalFnvm=m.p4+np4. □

Conclusion

We have characterized the local multiset dimension of amalgamation graphs. We have found the upper bound of local multiset dimension and determined the exact value of local multiset dimension of path Pn, complete graph Kn, wheel graph Wn, and fan graph Fn. There are some graphs that attain the upper bound of local multiset dimension namely wheel graphs. On the otherhand, we found the following problem, as follows.

Open Problem 0.1 Determine the lower bound of local multiset dimension of amalgamation graphs.

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Alfarisi R, Susilowati L, Dafik D and Prabhu S. Local Multiset Dimension of Amalgamation Graphs [version 1; peer review: 1 approved, 1 approved with reservations]. F1000Research 2023, 12:95 (https://doi.org/10.12688/f1000research.128866.1)
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Reviewer Report 31 Oct 2023
Muhammad Kamran Siddique, Department of Mathematics, COMSATS University Islamabad, Lahore, Pakistan 
Approved with Reservations
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Local Multiset Dimension of Amalgamation Graphs

I found that all the mathematical work is correct. Moreover paper is clearly written in a good way. It is new, as well as good contribution in the current area of ... Continue reading
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NOTE: it is important to ensure the information in square brackets after the title is included in all citations of this article.
  • Author Response 13 Apr 2024
    Liliek Susilowati, Mathematics, Universitas Airlangga, Surabaya, 68121, Indonesia
    13 Apr 2024
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    Thank you for your suggestion.
    I will revise my paper accordingly to your comments and suggestions.
    Competing Interests: No competing interests were disclosed.
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  • Author Response 13 Apr 2024
    Liliek Susilowati, Mathematics, Universitas Airlangga, Surabaya, 68121, Indonesia
    13 Apr 2024
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    Thank you for your suggestion.
    I will revise my paper accordingly to your comments and suggestions.
    Competing Interests: No competing interests were disclosed.
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Reviewer Report 26 Jan 2023
Ismail Naci Cangul, Department of Mathematics, Bursa Uludag University, Gorukle, Turkey 
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Set dimension in graph theory is a very applicable area which collected a lot of attention by many people. Here, the authors continued their research with local multiset dimension as a variant and studied this number for amalgamation graphs. Amalgamation ... Continue reading
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Cangul IN. Reviewer Report For: Local Multiset Dimension of Amalgamation Graphs [version 1; peer review: 1 approved, 1 approved with reservations]. F1000Research 2023, 12:95 (https://doi.org/10.5256/f1000research.141499.r161413)
NOTE: it is important to ensure the information in square brackets after the title is included in all citations of this article.
  • Author Response 10 Mar 2023
    Liliek Susilowati, Mathematics, Universitas Airlangga, Surabaya, 68121, Indonesia
    10 Mar 2023
    Author Response
    Dear Prof Ismail,

    For the abstract as there are "$" signs all around. The symbol "$", only editors can fix or remove the "$" sign. I've reported to the ... Continue reading
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  • Author Response 10 Mar 2023
    Liliek Susilowati, Mathematics, Universitas Airlangga, Surabaya, 68121, Indonesia
    10 Mar 2023
    Author Response
    Dear Prof Ismail,

    For the abstract as there are "$" signs all around. The symbol "$", only editors can fix or remove the "$" sign. I've reported to the ... Continue reading

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