ALL Metrics
-
Views
-
Downloads
Get PDF
Get XML
Cite
Export
Track
Research Article

Impact of high wind speed on blooming plants-honeybees-honey production model 

[version 1; peer review: awaiting peer review]
PUBLISHED 26 Dec 2025
Author details Author details
OPEN PEER REVIEW
REVIEWER STATUS AWAITING PEER REVIEW

This article is included in the Fallujah Multidisciplinary Science and Innovation gateway.

Abstract

Background

Local ecosystems and global agriculture are contingent upon the mutualistic relationship between pollinators and floral plants. In symbiosis, pollinators increase agricultural production by improving plant cross-pollination, genetic variety, crop quality, and yield. The potential impact on plant reproduction is particularly alarming due to the decline of pollinating insects. Habitat loss, diseases, climate change, pesticides, and predation have all contributed to the decline of pollinator species. High-speed wind is a significant factor that impacts the mutualistic relationship between plants and pollinators.

Methods

Studying the dynamics of interactions between blooming plants and honeybee populations is crucial for addressing honeybee decline and ensuring sustainable ecosystems. This work employs mathematical modeling to analyze the dynamics of a blooming plant, honeybee population, and honey production symbiosis, with a special emphasis on the effect of high-speed wind flow.

Results

The stability of various ecological equilibria has been investigated using dynamical system theory. Bifurcation phenomena, such as transcritical and Hopf bifurcations, have been discovered using bifurcation theory. Furthermore, the numerical results show that high wind flow can cause the extinction of the honeybee population and honey production.

Conclusions

Due to the rapid depletion of flowering plants and the high rate of wind speed, the populations of honeybees and blossoming plants are at risk of becoming unsustainable. However, the combination of reduced wind flow and increased symbiotic strengths can bolster the stability and sustainability of blooming plant-honeybee-honey production ecosystems. These findings inform conservation policies targeted toward protecting honeybees and increasing biodiversity.

Keywords

Wind speed, blooming plants-honeybees model, mutualistic relationship, Beddington-DeAngelis functional response, dynamical systems, stability analysis, bifurcation.

Introduction

The mutualistic relationship between blooming plants and honeybee populations is a crucial ecological interaction for the sustainability of both local ecosystems and global agricultural systems.1 Animal pollinators, including honeybees, provide pollination services through symbiosis, which is essential for the successful reproduction of approximately 300,000 plant species worldwide. In symbiosis, pollinators are vital for promoting plant cross-pollination, genetic diversity, and crop quality and yield, substantially contributing to agricultural productivity.2 Consequently, this is a critical research area in conservation biology and ecology. A significant number of studies have been undertaken regarding the symbiotic relationships between plants and pollinator systems.3 Hadani4 suggested that the symbiosis can be characterized by the Beddington-DeAngelis response function, which incorporates competition for resource exploitation among pollinators and the obligatory relationship between the plant and the pollinator. This relationship has been observed to maintain a steady state, provided that the initial population level is sufficiently substantial.5 Biswas et al. examined a plant–pollinator model to investigate the impact of predation on pollinator species. They conclude that the pollinator is at risk of extinction if the predation rate cannot be controlled. Moreover, this hypothesis has prompted the advancement of extensive studies examining the impacts of nectar theft and ants on the plant-pollinator system.6 The reduction of biodiversity is a widespread issue, although the decrease of pollinating insects is especially alarming due to its possible effects on plant reproduction.7 A recent report on the global reduction of honeybee and bumblebee populations has highlighted pollination’s ecological and economic significance.8 The reduction of pollinator species can be ascribed to various ecological and environmental reasons, including habitat loss, illnesses, climate change, pesticides, and predation.912 Invasive predators can significantly affect pollinators by diminishing their quantity, altering plant reproductive success, and undermining the plant-pollinator relationship.13

One factor that negatively affects the mutualism in plant-pollinator systems is high-speed wind.5,1417 High winds disrupt flower fragrance messages, reducing honeybee attraction. Strong winds quickly distribute flowers’ aromatic chemicals in different directions, reducing their “scent signal”. As aroma dispersion reduces, honeybees’ ability to discover food sources decreases, resulting in fewer trips to flowers.18 In addition, flying in severe winds demands more energy for balance and advancement. Honeybees may stay in the hive or fly less to preserve energy. Pollination opportunities decrease as fewer flowers are visited. Strong winds can break flowers’ petals or open their parts abnormally, decreasing honeybees’ access to their reproductive organs. This temporal shift may diminish pollination when flowers are most pollinating. High winds can cause honeybees to crash, fall, or be blown off course, destroying the colony. Lost workers or persistent stress can harm the colony and its capacity to provide enough workers for visits.19

In this study, we discuss the effect of high wind speed on a three-dimensional blooming plant–honeybee–honey production mathematical model ( phn model) that takes into account saturated mutualism between blooming plants and honeybees by the Beddington–DeAngelis response function. The primary focus is to investigate the dynamics of the plant–pollinator system while considering the impacts of wind speed on the mutualism between blooming plants and honeybees. The study aims to understand the interactions between mutualism and wind speed, and how these interactions affect the overall ecological balance and sustainability of the blooming plant–honeybee–honey production system.

Methods

Assumptions of the model

In this section, a phn model is formulated to describe the interaction among blooming plants p(t) , honey honeybees h(t) and the production of honey n(t) at time t . Then the blooming plant, the honey honeybees, and the production of honey system can be depicted by

(1)
dpdt=r1p(1pk1)+α1hp1+w+(ah+bp)γ1p,dhdt=r2h(1hk2)+α2hp1+w+(ah+bp)γ2h,dndt=α3h1+w+chβnhγ3n.
  • 1. The blooming plants are assumed to grow in the absence of honeybees at the intrinsic growth rate r1 , depletion rate γ1 and carrying capacity k1 . Since blooming plants provide nutrients for honeybees, honeybees offer pollination services to blooming plants; hence, their relationship is mutualistic. Beddington-DeAngelis functional response (α1hp1+w+(ah+bp)) can be used to express the mutualistic relationship, where α1 denotes the positive effect of honeybees (a kind of pollinator) on plants, a refers to the undepleted equilibrium rate for the blooming plant–honeybee interaction, which incorporates travel and unloading durations at a central location along with individual-level blooming plant–honeybee interactions, and b indicates the intensity of competition among honeybees for floral resources.

  • 2. High winds break plants’ stems and branches, causing flowers to collapse and damage their petals. This damage reduces the flowers’ attractiveness to pollinating insects. Also, wind speeds reduce the honeybees’ ability to search in a windy environment. Let ϑ(w)=11+w be the efficiency of wind, which satisfied the following

    • ϑ(0)=1 means in the absence of wind, the mutualistic interaction between blooming plants and honeybees remains as before, i.e., (α1hp1+(ah+bp)) .

    • ϑ(w)>1 means the efficiency of mutualistic interaction decreases in a high, windy environment.

  • 3. The honeybee population are expected to grow from external resources at the intrinsic growth rate r2 , depletion rate γ2 and carrying capacity k2 . (α2hp1+w+(ah+bp)) represents the nutrients that blooming plants provide to honeybees, where α2 stands for the corresponding value of honeybee nutrients from blooming plants.

  • 4. The term (α3h1+w+ch) represents the honey production in the colonies where α3 is the rate of production that is contingent upon the quantity of honeybees, and c is the half-saturation rate. Wind speed negatively affects the amount of honey produced since it diminishes the honeybees’ capacity to search for nutrition.

  • 5. During winter or drought, honeybees rely on their stored honey to survive. This represents a natural consumption process but diminishes the quantity available for harvest. Therefore, β signifies the rate at which honeybees consume honey to survive.

  • 6. The amount of honey produced decreases due to many factors, such as absorbing moisture from the atmosphere. In humid environments, honey absorbs moisture, which reduces its concentration and makes it susceptible to fermentation and spoilage. High temperatures cause the honey content to evaporate. Therefore, γ3 denotes the rate of natural causes of honey loss.

Further, the schematic sketch of phn system is illustrated in Figure 1.

ab09b08d-074d-48e2-9640-a8254f079bf8_figure1.gif

Figure 1. Flowchart of the phn model.

Model analysis

Before analyzing our model, it is pertinent to invoke the following lemmas, the demonstration of which is available in Refs. 20-22.

Lemma 1.

If H,>0 and Ḣ()H(HHα) , where a is a positive constant, when t0 and H(0)>0 , then

H(t)()(H)1/α[1+(HHa(0)1)eHαt]1/α

Lemma 2.

(Comparison lemma) Suppose that H,>0, with Ρ(0)>0 . Then for dtΡ(t)[HΡ(t)] , then limtsupP(t)H , and if dΡdtΡ(t)[HΡ(t)] , then limtinfP(t)H .

Uniqueness.

Since the right side of the phn model C1(R+3) , so they satisfy the Lipschitz condition. Therefore, the solution to phn model that starts in R+3 exists and is unique.

Positivity

Theorem 1.

The solution (p(t),h(t),n(t)) of phn system with the initial condition (p0,h0,n0) is positive.

Proof.

According to the blooming plants and honeybees’ equations of phn system, we get

p(t)=p0e0t(r1(1p(τ)k1)+α1h(τ)1+w+(ah(τ)+bp(τ))γ1)0
h(t)=h0e0t(r2(1h(τ)k2)+α2p(τ)1+w+(ah(τ)+bp(τ))γ2)0

From the equation for honey production, we attain

dndtn(βh0e0t(r2(1h(τ)k2)+α2p(τ)1+w+(ah(τ)+bp(τ))γ2)+γ3), which implies thatn(t)n0e0t(βh0e0t(r2(1h(τ)k2)+α2p(τ)1+w+(ah(τ)+bp(τ))γ2)+γ3)0

Therefore, the solution (p(t),h(t),n(t)) will remain positive for all t0 .

Boundedness

Theorem 2.

All solutions of phn system are uniformly bounded.

Proof.

From the blooming plants equation of the phn system, we obtain

dpdt=r1p(1pk1)+α1hp1+w+(ah+bp)γ1pp[(r1γ1)(r1pk1)+α1h] .

After using the honeybees’ carrying capacity, we get

dpdtp[(r1+α1k2γ1)(r1pk1)]

Using Lemma 1, we deduced that.

p(t)[(r1+α1k2γ1)k1r1]12(1+[(r1+α1k2γ1)k1p2(0)r11]e2(r1+α1k2γ1)t)12

It is obtained after taking t

p(t)[(r1+α1k2γ1)k1r1]12=pm

Similarly, for the honey honeybee equation of the phn system, we find

h(t)[k1(r2+α2pmγ2)r2]12=hm

Finally, from the amount of honey produced equation, we attain

dndt=α3h1+w+chβnhγ3nα3hmγ3n

Then, by Lemma 2, we get

0limtsup[n(t)]α3hmγ3=nm

Therefore, any solutions of phn system will be attracted to Σ={(h,p,n)R+3:p(t)pm,h(t)hm,n(t)nm} .

Persistence

The phn system is said to be persistent if all its components survive in future times.

Theorem 3.

All phn system components are persistent if

(2)
r1>γ1,
(3)
r2>γ2.

Proof:

First, to prove that p(t) If it is persistent, we have to show that limtinfp(t)>0 i.e. p(t) will not decay to zero.

From the blooming plants equation, we get

dpdt=r1p(1pk1)+α1hp1+w+(ah+bp)γ1pp[(r1γ1)(r1k1)p].

By Lemma 2, we have limtinfp(t)L1 , where L1=k1(r1γ1)r1 provided r1>γ1 . Thus, for a small E1>0 , a positive number t1>0 such that

p(t)L1E1t>t1

Applying the same strategy for the honeybee equation, we get

h(t)L2E2t>t2,
where L2=k2(r2γ2)r2 provided r2>γ2 .

From the honey production equation, we attain

dndt=α3h1+w+chβnhγ3nα3(L2E2)1+w+c(L2E2)n(βhmγ3)

Since

  • g(h)=α3h1+w+ch is an increasing function, which means if h(t)L2E2 , then g(h)g(L2E2)

  • h(t)hm

Then, by Lemma 2, limtinfn(t)α3(L2E2)[1+w+c(L2E2)](βhmγ3) , where L3=α3(L2E2)[1+w+c(L2E2)](βhmγ3)

Thus, for a small E3>0 , a positive number t3>0 such that

n(t)L3E3t>t3

Therefore, phn system is uniformly persistent.

Remark 1:

Conditions 2 and 3 indicate that all phn system components will survive in the future times if the intrinsic growth rates of the blooming plants and honeybees exceed their depletion rates.

Equilibrium analysis

The possible equilibria of phn system are

  • 1) The extinction point S1=(0,0,0) .

  • 2) The blooming plants point S2=(p1,0,0) , where p1=k1(r1γ1)r1 . For p1 to be positive, condition (2) must be satisfied.

  • 3) The honeybee point S3=(0,h2,0) , where h2=k2(r2γ2)r2 . Clearly h2>0 if condition (3) is satisfied.

  • 4) The blooming plants free point S4=(0,h3,n3) , where h3=k2(r2γ2)r2 and n3=α3h3(1+w+ch3)(βh3+γ3)>0 . Clearly h3>0 if the condition (3) is satisfied.

  • 5) The coexistence point S5=(p4,h4,n4) , here n4=α3h4(1+w+ch4)(βh4+γ3) , h4=r1bp42+z1p4+z2z3ar1p4 where,

    z1=r1(1+wk1b)+γ1k1b,

    z2=k1(γ1(1+w)(r1+w)),

    z3=k1(α1+a(r1γ1p)),

and p4 is the root of the following equation

(4)
A0p3+A1P2+A2P+A3=0,
where,

A0=r1[r1a(r2b+r2bw+α2ak2)r2b(bz3+az1)],

A1=(r2γ2)[r1(ak2(r1+war1bz3az1)]+r2(az1+awz1bwbwz3abz2)r2bz1z3r2az12 ar1α2z3k2aα2r1z3k2,

A2=(r2γ2)[z3k2(z3br12r1aw+az1r1a)k2r1a2z2]+r2(z2(a(r12z1+wr1)bz3) +z3(k2α2r1z1w)),

A3=(r2γ2)[z3(z3k2(wz3az2))]r2z2(z3+wz3+az2).

By Descartes’s rule of signs, Equation (4) has a unique positive root p4 , if one of the following conditions holds:

A0>0,andA2,A3<0,A0,A1>0,andA3<0,A0<0,andA2,A3>0,A0,A1<0,andA2,A3>0.

Further, h4>0 if one of the following conditions holds:

r1bp42+z1p4+z2>0andz3>ar1p4r1bp42+z1p4+z2<0andz3<ar1p4

Local stability of equilibrium points

To investigate the local stability, one needs to determine the Jacobian matrix at any point. Thus, the Jacobian matrix at any point (p,h,n) is

J(p,h,n)=[a11α1p(1+w+bp)(1+w+(ah+bp))20α2h(1+w+ah)(1+w+(ah+bp))2a2200α3(1+w)(1+w+ch)2βnβhγ3],
where a11=2r1pk1+α1h(1+w+ah)(1+w+(ah+bp))2+(r1γ1) , and a22=2r2hk2+α2p(1+w+bp)(1+w+(ah+bp))2+(r2γ2) .
Theorem 4.

The extinction point S1=(0,0,0) is locally asymptotically stable if

(5)
γ1>r1,
(6)
γ2>r2.

Proof:

The Jacobian matrix at S1=(0,0,0) is

(7)
J(S1)=[r1γ1000r2γ20031+wγ3],

Then, the eigenvalues of J(S1) are λ11=r1γ1 , λ12=r2γ2 and λ13=γ3<0 .

Therefore, S1 is asymptotically stable under conditions 5 and 6.

Remark 2:

The biological interpretation of conditions 5 and 6 indicates phn system reaches asymptotically the extinction point when the depletion rates of the blooming plants and honeybees exceed their intrinsic growth rates.

Theorem 5.

The blooming plants point S2=(p1,0,0) is locally asymptotically stable if

(8)
r2+α2p1(1+w+bp1)<γ2,

Proof:

J(S2)=J(p1,0,0) is given by

(9)
J(S2)=[(r1γ1)α1p1(1+w+bp1)00α2p1(1+w+bp1)+(r2γ2)00α31+wγ3].

So, the eigenvalues of S2 are

λ21=(r1γ1)<0 , under the existence condition of the blooming plants point.

λ22=α2p1(1+w+bp1)+(r2γ2), and λ23=γ3<0 .

Thus, S2 is asymptotically stable if condition 8 is satisfied .

Theorem 5.

The honeybee point S3=(0,h2,0) is locally asymptotically stable if

(10)
r1+α1h2(1+w+ah2)<γ1,
(11)
(r2γ2)<2r2h2k2

Proof:

J(S3)=J(0,h2,0) is given by

(12)
J(S3)=[α1h2(1+w+ah2)+(r1γ1)00α2h21+w+ah2(r2γ2)2r2h2k200α3(1+w)(1+w+ch2)2βh2γ3].

So, the eigenvalues of J(S3) are λ31=α1h2(1+w+ah2)+(r1γ1),λ32=(r2γ2)2r2h2k2 , and λ33=βh2γ3<0 . Thus, S3 is asymptotically stable if the conditions 10 and 11 are satisfied.

Theorem 6.

The blooming plants free point S4=(0,h3,n3) is locally asymptotically stable if

(13)
r1+α1h3(1+w+ah3)<γ1,
(14)
(r2γ2)<r2h3k2

Proof:

J(S4)=J(0,h3,n3) is given by

(15)
J(S4)=[α1h3(1+w+ah3)+(r1γ1)00α2h3(1+w+ah3)(r2γ2)2r2h3k200α3(1+w)(1+w+ch3)βn3βh3γ3].

The eigenvalues of J(S4) are λ41=α1h3(1+w+ah3)+(r1γ1) , λ42=(r2γ2)2r2h3k2 , and λ43=βh3γ3<0 . So, S4 is asymptotically stable if conditions 13 and 14 are satisfied.

Theorem 7.

The coexistence point S5=(p4,h4,n4) is locally asymptotically stable if

(16)
aii<0,i=1,2,
(17)
a11a22>[α1α2p4h4(1+w+bp4)(1+w+ah4)(1+w+(ah4+bp4))4].

Proof:

J(S5)=J(p4,h4,n4) is given by

(18)
J(S5)=[a11α1p4(1+w+bp4)(1+w+(ah4+bp4))20α2h4(1+w+ah4)(1+w+(ah4+bp4))2a2200α3(1+w)(1+w+ch4)2βn4βh4γ3],
where a11=(r1γ1)2r1p4k1+α1h4(1+w+ah4)(1+w+(ah4+bp4))2 , and a22=(r2γ2)2r2h4k2+α2p4(1+w+bp4)(1+w+(ah4+bp4))2 .

Then, the characteristic equation of J(S5) is given by:

(19)
(βh4γ3λ)[λ2Trλ+Det]=0,

where,

λ51=βh4γ3,Tr=a11+a22=(r1γ1)2r1p4k1+α1h4(1+w+ah4)(1+w+(ah4+bp4))22r2h4k2+α2p4(1+w+bp4)(1+w+(ah4+bp4))2+(r2γ2),Det=a11a22[α1α2p4h4(1+w+bp4)(1+w+ah4)(1+w+(ah4+bp4))4]=((r1γ1)2r1p4k1+α1h4(1+w+ah4)(1+w+(ah4+bp4))2)((r2γ2)2r2h4k2+α2p4(1+w+bp4)(1+w+(ah4+bp4))2)[α1α2p4h4(1+w+bp4)(1+w+ah4)(1+w+(ah4+bp4))4].

Thus, S5 exhibits local stability if conditions 16 and 17 are fulfilled.

Global stability

In this section, the Lyapunov method is used to illustrate the global stability of the previous points, as shown in the following theorems.

Theorem 8.

The extinction point S1=(0,0,0) is a global asymptotic stability (GAS) if the following conditions are met.

(20)
r1+hm(α1+α2)1+w<γ1
(21)
r2+α31+w<γ2

Proof:

Let E1(p,h,n)=p+h+n , where E1:R+3R , which satisfies E1(0,0,0)=0 and E1(p,h,n)>0 for all (p,h,n)R+3 with (p,h,n)(0,0,0) . Then

dE1dt=dpdt+dhdt+dndt=(r1p(1pk1)+α1hp1+w+(ah+bp)γ1p)+(r2h(1hk2)+α2hp1+w+(ah+bp)γ2h)+(α3h1+w+ch)βnhγ3n)=r1pr1p2k1+hp(α1+α2)1+w+(ah+bp)γ1p+r2hr2h2k2γ2h+α3h1+w+ch)βnhγ3n

Then, by using the upper bound of the honeybees’ population, we get

dE1dtp(r1γ1+hm(α1+α2)1+w)+h(r2γ2+α31+w)r1p2k1r2h2k2βnhγ3n.

The first two terms are negative definite if conditions 20 and 21 are satisfied. Hence, dE1/dt is a negative definite. Therefore, the extinction point S1 is GAS.

Theorem 9.

The blooming plants point S2=(p1,0,0) is GAS if

(22)
r2+α2pm+α31+w<γ2,
(23)
(α1D)2r1r2k1k2,
where, D=1+w+(ah+bp) .

Proof:

Let E2=(pp1p1ln(pp1))+h+n , where E2:R+3R , which satisfies E2(p1,0,0)=0 and E2(p,h,n)>0 for all (p,h,n)R+3 with (p,h,n)(p1,0,0) , then

dE2dt=(pp1p)dpdt+dhdt+dndt=r1k1(pp1)2+α1h(pp1)D+hr2(1hk2)+α2phDγ2h+α3h1+w+chβnhγ3n

Then, by using the upper bound of the blooming plants population, we get

dE2dt(r1k1(pp1)2α1Dh(pp1)+r2k2h2)+h(r2+α2pm+α31+wγ2)βnhγ3n.

Thus,

dE2dt(r1k1(pp1)+r2k2h)2+h(r2+α2pm+α31+wγ2)βnhγ3n.

The first two terms are negative definite if conditions 22 and 23 are satisfied. Hence, dE2/dt is a negative definite. Therefore, the blooming plants point S2=(p1,0,0) is GAS.

Theorem 10.

The honeybee point S3=(0,h2,0) , is GAS if

(24)
r1+α1hm1+w<γ1,
(25)
(α2D)2r1r2k1k2,
(26)
α3β(1+w)<n,
where, D=1+w+(ah+bp) .

Proof:

Let E3=p+(hh2h2lnhh2)+n , where E3:R+3R , which satisfies E3(0,h2,0)=0 and E3(p,h,n)>0 for all (p,h,n)R+3 with (p,h,n)(0,h2,0) , then

dE3dt=dpdt+(hh2h)dhdt+dndt=(r1p(1pk1)+α1hp1+w+(ah+bp)γ1p)+(hh2)((r2(1hk2)+α2p1+w+(ah+bp)γ2))+(α3h1+w+chβnhγ3n)r1pr1p2k1+α1hp1+wγ1pr2k2(hh2)2+α2(hh2)pD+α3h1+wβnhγ3n

Then, by using the upper bound of the honeybees’ population, we get

dE3dt(r1k1p2α2(hh2)pD+(r2k2)(hh2)2)+p(r1+α1hm1+wγ1)+h(α31+wβn)γ3n

Thus,

dE3dt(r1k1p+r2k2(hh2))2+p(r1+α1hm1+wγ1)+h(α31+wβn)γ3n.

The first three terms are negative definite if conditions 24-26 are satisfied. Hence, dE3/dt is a negative definite. Therefore, the blooming plants point S3=(0,h2,0) is GAS.

The blooming plants free point S4=(0,h3,n3)

Theorem 11.

The blooming plants free point S4=(0,h3,n3) is GAS if

(27)
(α2D)2r1r22k1k2,
(28)
(α3(1+w)D1D2βn)2r2(βh3+γ3)2k2,
where, D=1+w+(ah+bp),D1=(1+w+ch) and D2=(1+w+ch3) .

Proof:

Let E4=p+(hh3h3lnhh3)+(nn32)2 , where E4:R+3R , which satisfies E4(0,h3,n3)=0 and E4(p,h,n)>0 for all (p,h,n)R+3 with (p,h,n)(0,h3,n3) , then

dE4dt=dpdt+(hh3h)dhdt+(nn3)dndt=(r1p(1pk1)+α1hp1+w+(ah+bp)γ1p)+(hh3)(r2(1hk2)+α2p1+w+(ah+bp)γ2)+(nn3)(α3h1+w+chβnhγ3n)=r1pr1p2k1+α1hp1+w+(ah+bp)γ1p+(hh3)(r2k2(hh3)+α2p1+w+(ah+bp))+(nn3)(α3h1+w+chα3h31+w+ch3βnhβn3h3γ3(nn3))

Then, by using the upper bound of the honeybees’ population, we get

dE4dt(r1k1p2α2(hh3)p1+w+(ah+bp)+(r22k2)(hh3)2)+p(r1+α1hm1+wγ1)[(r22k2)(hh3)2(α3(1+w)(1+w+ch)(1+w+ch3)βn)(hh3)(nn3)+(βh3+γ3)(nn3)2]

Thus,

dE4dt(r1k1p+r22k2(hh3))2+p(r1+α1hm1+wγ1)(r22k2(hh3)+(βh3+γ3)(nn3))2

The first and the third terms are negative definite if conditions 27 and 28 are satisfied, while the second term is negative under condition 24. Hence, dE4/dt is a negative definite. Therefore, the blooming plants free point S4=(0,h3,n3) is GAS.

Theorem 12.

The coexistence point S5=(p4,h4,n4) is GAS if

(29)
((α1+α2)(1+w)+α1bp4+α2ah4N1N2)212(r1k1+α1bh4N1N2)(r2k2+α2ap4N1N2),
(30)
(α3(1+w)D1D2βn)212(r2k2+α2ap4N1N2)(βh4+γ3),
where, N1=1+w+(ah+bp) , N2=1+w+(ah4+bp4),D1=(1+w+ch) and D2=(1+w+ch3) .

Proof: Let E5=(pp4p4lnpp4)+(hh4h4lnhh4)+(nn42)2 , where E5:R+3R , which satisfies E5(p4,h4,n4)=0 and E5(p,h,n)>0 for all (p,h,n)R+3 with (p,h,n)(p4,h4,n4) , then

dE5dt=(pp4p)dpdt+(hh4h)dhdt+(nn4)dndt=(pp4)(r1(1pk1)+α1h1+w+(ah+bp)γ1)+(hh4)(r2(1hk2)+α2p1+w+(ah+bp)γ2)+(nn4)(α3h1+w+chβnhγ3n)dE5dt=[(r1k1+α1bh4N1N2)(pp4)2((α1+α2)(1+w)+α1bp4+α2ah4N1N2)(pp4)(hh4)+12(r2k2+α2ap4N1N2)(hh4)2][12(r2k2+α2ap4N1N2)(hh4)2(α3(1+w)D1D2βn)(nn4)(hh4)+(βh4+γ3)(nn4)2]

Thus,

dE5dt((r1k1+α1bh4N1N2)(pp4)+12(r2k2+α2ap4N1N2)(hh4))2(12(r2k2+α2ap4N1N2)(hh4)+(βh4+γ3)(nn4))2

Hence, dE5/dt is a negative definite under conditions 29 and 30. Therefore, the coexistence point S5=(p4,h4,n4) is GAS.

Bifurcation

This section explores the probability of occurrence of transcritical (TB) and Hopf bifurcation (HB) around the non-hyperbolic equilibrium points. For more details, see Refs. 23-26.

Theorem 13.

For r2=γ2 , the phn model faces TB at the extinction point S1=(0,0,0) .

Proof:

According to J(S1) given by Eq. (7), the phn system at S1 has a zero eigenvalue λ12=0 , at r2=γ2 , and J(S1) at r2=γ2 becomes

J(S1)=[r1γ000000α31+wγ3]

Now, suppose that ϑ[1]=(ϑ1[1],ϑ2[1],ϑ3[1])T , and (T[1])T=(t1[1],t2[1],t3[1])T be eigenvectors to λ22=0 of J(S1) , and JT(S1) , respectively. The calculation gives ϑ[1]=(0,1,α3γ3(1+w) ), and (T[1])T=(0,1,0) by solving (J(S1)λ12I)ϑ[1] , and (JT(S1)λ12I)T[1] for ϑ[1] and T[1] .

Further,

Fr2(S,r2)=(0,h(1hk2),0)Fr2(S1,r2)=(0,0,0)
(T[1])TFr2(S1,r2)=(0,1,0)(0,0,0)=0
(T[1])TDFr2(S1,r2)ϑ[1]=(0,1,0)[000010000]=10
(T[1])TD2Fr2(S1,r2)(ϑ[1],ϑ[1])=(0,1,0)[02r2k20]=2r2k20

Therefore, there is a TB around S1 with the parameter r2=γ2 .

Theorem 14.

For r1=γ1 , the phn model faces TB at the extinction point S2=(p1,0,0) if

(30)
p1=k1,
(31)
(T[2])TD2Fr1(S2,r1)(ϑ[2],ϑ[2])0

Proof:

According to J(S2) given by Eq. (9), the phn system at S2 has a zero eigenvalue λ22=0 , at r1=γ1 , and J(S2) at r1=γ1 becomes

J(S2)=[0000r2γ200α31+wγ3],

Now, suppose that ϑ[2]=(ϑ1[2],ϑ2[2],ϑ3[2])T and (T[1])T=(t1[2],t2[2],t3[2])T be eigenvectors with respect to λ22=0 of J(S2) and JT(S2) respectively. Solving (J(S2)λ22I)ϑ[2]=0 , and (JT(S2)λ22I)T[2]=0 for ϑ[2] , and T[2] gives ϑ[2]=(1,1,α3γ3(1+w))T and (T[2])T=(1,α3(1+w)(γ2r2),1)T , where (γ2r2)0 .

Further,

Fr1(S,r1)=(p(1pk1),0,0)Fr1(S2,r1)=(p1(1p1k1),0,0)
(T[2])TFr1(S2,r1)=(1,3(1+w)(γ2r2),1)(p1p12k1,0,0)=p1(1p1k1)=0under condition30.
(T[2])TDFr1(S2,r1)(ϑ[2])=(1,α3(1+w)(γ2r2),1)[100000000]=10

(T[2])TD2Fr1(S2,r1)(ϑ[2],ϑ[2])=(1,α3(1+w)(γ2r2),1)[X11[2]+X12[2]X21[2]+X22[2]X32[2]+X33[2]3γ3(1+w)]

=(X11[2]+X12[2])+α3(1+w)(γ2r2)(X21[2]+X22[2])+(X32[2]+X33[2]α3γ3(1+w))0

under condition 31, here, X11[2]=2r1k1+[α1[(1+w)](1+w+bp1)2] , X12[2]=[α1(1+w)(1+w+bp1)2]+[2aα1p1(1+w+bp1)2] , X21[2]=[α2(1+w)(1+w+bp1)2] , X22[2]=[α2[(1+w)](1+w+bp1)2]+[2r2k22aα2p1(1+w+bp1)2] , X32[2]=2cα3(1+w)2βα3γ3(1+w),andX33[2]=βα3γ3(1+w).

Therefore, there is a TB around S2 with the parameter r1=γ1 .

Theorem 15.

For r2=γ2k2k22h2 , the phn model faces TB at the honeybee point S3=(0,h2,0) if

(32)
h2=k2,

Proof:

According to J(S3) given by Eq. (11), the phn system at S3 has a zero eigenvalue λ32=0 , at r2 , and J(S3) at r2 becomes

J(S3)=[α1h21+w+ah2+(r1γ1)00αh21+w+ah2000(1+w)α3(1+w+ch2)2(βh2+γ3)] .

Now, Suppose that ϑ[3]=(ϑ1[3],ϑ2[3],ϑ3[3]) and (T[3])T=(t1[3],t2[3],t3[3])T be eigenvectors to λ32=0 of J(S3) and JT(S3) respectively. Solving (J(S3)λ32I)ϑ[3]=0 , and (JT(S3)λ32I)T[3]=0 for ϑ[3] and T[3] gives V[3]=(0,1,α3(1+w)(βh2+γ3)(1+w+ch2)2) and (T[3])T=(α2h2(α1h2+(r1γ1)(1+w+ah2)),1,0) , where [α1h2+[(r1γ1)(1+w+ah2)]0 .

Further

Fr2(S3,r2)=(0,hhk2,0)Fr2(S3,r2)=(0,h2(1h2k2),0)(T[3])TFr2(S3,r2)=(α2h2(α1h2+(r1γ1)(1+w+ah2)),1,0)(0,h2(1h2k2),0)(T[3])TFr2(S3,r2)=h2(1h2k2)=0under condition32.(T[3])TDFr2(S3,r2)(ϑ[3])=(α2h2(α1h2+(r1γ1)(1+w+ah2)),1,0)[000010000]=10(T[3])TD2Fr2(S3,r2)(ϑ[3],ϑ[3])=(α2h2(α1h2+(r1γ1)(1+w+ah2)),1,0)[02r2k2X32[3]βα3(1+w)(βh2+γ2)(1+w+ch2)2]=2r2k20,
where X32[3]=2cα3(1+w)(1+w+ch2)3βα3(1+w)(βh2+γ2)(1+w+ch2)2

Therefore, there is a TB around S3 with the parameter r2 .

Theorem 16.

For r2=γ2k2k22h3 , the phn model faces TB at the honeybee point S4=(0,h3,n3) if

(33)
h3=k2,

Proof:

According to J(S4) given by Eq. (15), the phn system at S4 has a zero eigenvalue λ42=0 , at r2 , and J(S4) at r2 becomes

J(S4)=[a1100a21000a32βh3γ3],
where, a11=α1h3(1+w+ah3)+(r1γ1) , a21=α2h31+w+ah3 and a32=α3(1+w)(1+w+ch3)βn3 .

Now, Suppose that ϑ[4]=(ϑ1[4],ϑ2[4],ϑ3[4]) , and (T[4])T=(t1[4],t2[4],t3[4]) be an eigenvector of to λ42=0 of J(S4) and JT(S4) , respectively, which gives ϑ[4]=(0,1,a32βh3+γ3) and (T[4])T=(a21a11,1,0) .

Further,

Fr2(S,r2)=(0,h(1hk2),0)Fr2(S4,r2)=(0,h2h2k2,0)(T[4])TFr2(S3,r2)=(a21a11,1,0)(0,h32h32k2,0)=h3(1h3k2)=0under condition33.(T[4])TDFr2(S4,r2)(ϑ[4])=(a21a11,1,0)[000010000]=10(T[4])TD2Fr2(S4,r2)(ϑ[4],ϑ[4])=(a21a11,1,0)[02r2k22cα3(1+w)(1+w+ch3)3+β(a32βh3+γ3)2]=2r2k20,

Therefore, there is a TB around S4 with the parameter r2 .

Theorem 17.

The phn undergoes a Hopf bifurcation at the coexistence point S5 to the bifurcation parameter w if

(34)
[Det]|w=w>0,
(35)
bα1p4h4+aα2p4h4α1h4(1+w+ah4)+α2p4(1+w+bp4),
where the formula of w is given in the proof.

Proof.

The Jacobian matrix at S5 with w is given by

J(S5,w)=[a11α1p4(1+w+bp4)(1+w+(ah4+bp4))20α2h4(1+w+ah4)(1+w+(ah4+bp4))2a2200α3(1+w)(1+w+ch4)2βn4βh4γ3],

where a11=(r1γ1)2r1p4k1+α1h4(1+w+ah4)(1+w+(ah4+bp4))2 , and a22=(r2γ2)2r2h4k2+α2p4(1+w+bp4)(1+w+(ah4+bp4))2 .

The Hopf bifurcation occurred if the following conditions are satisfied.

  • 1. [Tr]|w=w=0 ,

  • 2. [Det]|w=w>0 ,

  • 3. ∂w[Re(λ1,2)]w=w0 (Transversality condition),

where Tr and Det are defined in the characteristic equation given by (19). Now, we set Tr=0 to find w , which gives

Tr=0(r1γ1)2r1p4k1+α1h4(1+w+ah4)(1+w+(ah4+bp4))22r2h4k2+α2p4(1+w+bp4)(1+w+(ah4+bp4))2+(r2γ2)=0.

Let b1=(r1γ1)+(r2γ2)2r1p4k12r2h4k2 , b2=(ah4+bp4) , b3=α1ah42+α2bp42 , b4=(α1h4+α2p4) , and v=(1+w) . Then

Tr=0b1+b4v+b3(v+b2)2=0

Solving the above equation for v , gives

(v+b2)2b1+b4v+b3=0

Then,

(v+b2)2b1+b4v+b3=0b1v2+(2b1b2+b4)v+(b1b22+b3)=0.

The discriminant of the above equation is

Δ=(2b1b2+b4)24b1(b1b22+b3)=b42+4b1(b2b4b3).

Thus,

v=(2b1b2+b4)±Δ2b1,w=v1,b10

That means condition (1) is satisfied at w , and the characteristic equation given by (19) can be rewritten as

(βh4γ3λ)[λ2+Det]=0

Solving the above equation yields λ1=βh4γ3 , λ2,3=±iDet . Clearly λ2 and λ3 are complex conjugates if condition 34 is satisfied. In addition, the general roots of Eq. (19) in the neighborhood of w as λ2,3=Tr±iTr24Det2 , then

∂w[Re(λ2,3)]w=w=bα1p4h4+aα2p4h4α1h4(1+w+ah4)α2p4(1+w+bp4)(1+w+(ah4+bp4))30under condition35.

So, phn system undergoes a Hopf bifurcation at S5 with the bifurcation parameter w .

Numerical simulations and discussion

A numerical confirmation is carried out to complete the analytical results for phn system using MATLAB. The simulations are conducted by using the following set of parameters.

(36)
r1=0.56,k1=10,α1=0.04,w=3,a=0.02,b=0.03γ1=0.04,r2=0.18,k2=6,α2=0.08=0.4,γ2=0.03,α3=0.01,β=0.00157,γ3=0.0018,c=0.01.

For the parameters listed above in Eq. (36), the nullclines of phn system are indicated in Figure 2. The figure depicts the coexistence point S5=(p4,h4,n4)=(0.21,0.11,0.23) , while Figure 3 illustrates the global behavior of S5 . That means the parameters listed in Eq. (36) corroborate the findings of Theorem 12, which shows that all other points act as saddle points, except for S5 . These findings also confirm the uniform persistence for phn system, which confirms the output of Theorem 3.

ab09b08d-074d-48e2-9640-a8254f079bf8_figure2.gif

Figure 2. The nullclines of phn system with the parameters listed in Eq. (36).

ab09b08d-074d-48e2-9640-a8254f079bf8_figure3.gif

Figure 3. The global stability of S5=(0.21,0.11,0.23) .

An important parameter to investigate is the effect of the wind level (w) on the interaction of blooming plants p(t) , honey honeybees h(t), and honey production n(t) . We address two aspects of w : first, the extent to which it influences the species densities in the inner equilibrium, and second, how it can alter phn system’s stability. For a low level of wind flow, i.e., 0<w<0.017, the solution of the phn system approaches a chaotic attractor, see Figure 4(a). While in the interval 0.017<w0.74 , the solution of the phn system converges to a limit cycle, see Figure 4(b) and Figure 5. Consequently, for the region 0.74<w<3.4 , the solution stabilized at the coexistence point S5 , see Figure 2, which was plotted when w=3 . Finally, for a high level of wind speed, i.e., for w>3.4 , phn system loses two of its components, and the solution in this case settles down to the blooming plants’ point S2=(0.16,0,0) , see Figure 4(c). This indicates that when the wind speed is light, the wind helps pollinate or carries the seeds of flowering plants from one place to another, aiding their reproduction. Therefore, the presence of flowering plants contributes to the system’s persistence. In contrast, for a high wind flow, we see that the populations of honeybees and the production of honey face extinction.

ab09b08d-074d-48e2-9640-a8254f079bf8_figure4.gif

Figure 4. The effect of various wind speeds w .

ab09b08d-074d-48e2-9640-a8254f079bf8_figure5.gif

Figure 5. Hopf bifurcation at w=0.74 .

Now, we have the intrinsic growth rate of the honeybee population ( r2) , which is an essential quantity to discuss since it can potentially influence the population’s densities of blooming plants, honeybees, and honey production. It is clear from Figure 6 that the solution of phn system settles down to the coexistence point S5 for r2>0.03 , while it stabilized at the extinction point S1=(0,0,0) for r20.03 . This result confirms the occurrence of a transcritical bifurcation at r2=r2TB=0.03 , which confirms the output of Theorem 13, see Figure 7. Further, Figure 8 indicates the global behavior of the extinction point S1 . This result confirms the global stability condition of S1 which has honeybee stated in Theorem 8. Further, this result shows that r2 is a critical parameter that impacts the continuity of the whole system’s coexistence.

ab09b08d-074d-48e2-9640-a8254f079bf8_figure6.gif

Figure 6. The effect of varying r2 .

ab09b08d-074d-48e2-9640-a8254f079bf8_figure7.gif

Figure 7. Transcritical bifurcation at r2=0.03 .

ab09b08d-074d-48e2-9640-a8254f079bf8_figure8.gif

Figure 8. The global stability of S1 .

The effect of varying the intrinsic growth rate r1 of the population of blooming plants is investigated in Figure 9. The figure indicates that the solution of phn system converges to the blooming plants point S2=(0.28,0,0) for r10.04 , which means the system faces an occurrence of transcritical bifurcations at r1=r1TB = 0.04, which confirms the output of Theorem 14. So, phn system loses two of its components for r10.04 . While for r1>0.04 , phn system converges to the coexistence point S5 . Further, the global stability of S2 is illustrated in Figure 10. We can conclude that the intrinsic growth rate r1 of the blooming plants population is a critical parameter affecting the honeybees’ persistence and honey production.

ab09b08d-074d-48e2-9640-a8254f079bf8_figure9.gif

Figure 9. The effect of varying r1 .

ab09b08d-074d-48e2-9640-a8254f079bf8_figure10.gif

Figure 10. The global stability of S2 .

The mutualistic rates between the honeybee population and the blossoming plants, α1 and α2 , are examined in Figures 11 and 12. The density of blossoming plants, the honeybee population, and honey production are all improved as a result of the increase in mutualistic rates.

ab09b08d-074d-48e2-9640-a8254f079bf8_figure11.gif

Figure 11. The effect of varying α1 .

ab09b08d-074d-48e2-9640-a8254f079bf8_figure12.gif

Figure 12. The effect of varying α2 .

A rise in the depletion rate of the population of blossoming plants population γ1 (when γ1=0.57) leads to losses of the honeybee population and honey in phn system, and the solution stabilized at the honeybee point S3=(0,0.52,0) from various initial conditions. This result confirms the global stability theorem of S3 which was stated in Theorem 10. As a result, the continued presence of a blossoming plant population significantly impacts the persistence of honey production since the flowering plants are the primary source of sustenance for pollinators. See Figure 13.

ab09b08d-074d-48e2-9640-a8254f079bf8_figure13.gif

Figure 13. The global stability of S3 when γ1=0.57 .

To establish the effect of β on the dynamics of phn , Figure 14 has been drawn with three values of the rate at which honeybees consume honey to survive, i.e., β . The figure shows the solutions settling down to the coexistence point S5 . The increase in β substantially results in a decline in honey output.

ab09b08d-074d-48e2-9640-a8254f079bf8_figure14.gif

Figure 14. The effect of varying β .

In order to investigate the sensitivity of the coexistence point S5=(p4,h4,n4) of phn system, we implement partial rank correlation coefficients (PRCC). The parameters r1,k1,α1,w,a,b,γ1,r2,k2,α2,γ2,β,γ3,c and α3 serve as input parameters, whereas p4,h4, and n4 the output variables. We subsequently generate Figure 15 by utilizing the parameter set in Eq. (36). Blossoming plants and the honeybee population demonstrate heightened sensitivity to honeybees’ carrying capacity k2 and the corresponding value of honeybee nutrients from blooming plants α2 . While the honey production determines heightened sensitivity to α3 . On the other hand, the wind flow, i.e., w, significantly influences p4 , h4 and n4 . The wind flow significantly reduces the blooming plants, honeybee population, and honey production. It can be inferred that the wind flow is a critical parameter that influences the coexistence of p4,h4, and n4 , see Figure 15.

ab09b08d-074d-48e2-9640-a8254f079bf8_figure15.gif

Figure 15. The sensitivity of the data given in Eq. 36 relative to the S5=(p4,h4,n4) .

Conclusion

Wind flow profoundly affects blossoming plants, honeybee populations, and honey production dynamics, and impacts ecosystem stability. An ODE mathematical model has been studied to understand these dynamics. The solution of phn system has been established to possess the fundamental attributes, such as positivity and persistence, boundedness, local and global stability, and bifurcation. Numerical results indicated that the honeybee species may be extinct due to increased wind velocities within specific parameter ranges. Furthermore, the coexistence equilibrium becomes unstable as a result of a Hopf bifurcation when a low wind flow induces periodic oscillations. Further, the simulations indicated that the threshold values for the transcritical bifurcation have been precisely determined at a decreased honeybee and blooming plant growth rate. However, the system may reach a point where both the blooming plant and the honeybee populations are no longer viable due to an elevated mortality rate of flowering plants. On the other hand, the increase in mutualistic rates between the honeybee population and the blooming plants has a regenerative effect, supporting the sustainability of the honeybee–honey production system.

Comments on this article Comments (0)

Version 1
VERSION 1 PUBLISHED 26 Dec 2025
Comment
Author details Author details
Competing interests
Grant information
Copyright
Download
 
Export To
metrics
Views Downloads
F1000Research - -
PubMed Central
Data from PMC are received and updated monthly.
- -
Citations
CITE
how to cite this article
Jawad S and AL-Aali ZHA. Impact of high wind speed on blooming plants-honeybees-honey production model  [version 1; peer review: awaiting peer review]. F1000Research 2025, 14:1459 (https://doi.org/10.12688/f1000research.172134.1)
NOTE: If applicable, it is important to ensure the information in square brackets after the title is included in all citations of this article.
track
receive updates on this article
Track an article to receive email alerts on any updates to this article.

Open Peer Review

Current Reviewer Status:
AWAITING PEER REVIEW
AWAITING PEER REVIEW
?
Key to Reviewer Statuses VIEW
ApprovedThe paper is scientifically sound in its current form and only minor, if any, improvements are suggested
Approved with reservations A number of small changes, sometimes more significant revisions are required to address specific details and improve the papers academic merit.
Not approvedFundamental flaws in the paper seriously undermine the findings and conclusions

Comments on this article Comments (0)

Version 1
VERSION 1 PUBLISHED 26 Dec 2025
Comment
Alongside their report, reviewers assign a status to the article:
Approved - the paper is scientifically sound in its current form and only minor, if any, improvements are suggested
Approved with reservations - A number of small changes, sometimes more significant revisions are required to address specific details and improve the papers academic merit.
Not approved - fundamental flaws in the paper seriously undermine the findings and conclusions
Sign In
If you've forgotten your password, please enter your email address below and we'll send you instructions on how to reset your password.

The email address should be the one you originally registered with F1000.

Email address not valid, please try again

You registered with F1000 via Google, so we cannot reset your password.

To sign in, please click here.

If you still need help with your Google account password, please click here.

You registered with F1000 via Facebook, so we cannot reset your password.

To sign in, please click here.

If you still need help with your Facebook account password, please click here.

Code not correct, please try again
Email us for further assistance.
Server error, please try again.